← Grade 10 Science

Pressure

Unit 8 · CDC textbook pages 197–223

नेपालीमा पढ्नुहोस्

In this unit 10 sections
  1. Pressure: a push spread over an area
  2. Pressure in liquids and air
  3. Transmission of pressure
  4. Pascal’s law
  5. Hydraulic machines
  6. Upthrust
  7. Archimedes’ principle
  8. Flotation
  9. Project work
  10. Exercise

A ship made of 50,000 tonnes of steel floats, yet one steel nail sinks. A mechanic lifts a whole bus with one hand on a small jack. A hen’s egg sinks in a glass of tap water, then floats after you stir in a few spoons of salt. And a bucket in a well feels light as long as it is under water, then suddenly heavy as it comes out.

All of these are about pressure in fluids: how liquids and gases push on everything they touch, how they pass a push from one place to another, and how they push things up. By the end of this unit you will be able to explain every one of them, and work out how big the forces are.

Pressure: a push spread over an area

Put a brick on a sponge or a piece of foam and it sinks in. The brick’s weight presses on the foam. A water pipe that bursts was pushed apart from the inside by the water. And in the trick of Figure 8.1, a card holds a glass of water upside down: the air pushes the card up. Solids, liquids and gases all push on the surfaces they touch.

A push that acts at right angles (perpendicular) to a surface is called thrust. It is a force, so its SI unit is the newton (N). The thrust acting on each unit of area is the pressure:

pressure (P)=thrust (F)area (A) \text{pressure } (P) = \frac{\text{thrust } (F)}{\text{area } (A)}

The SI unit of pressure is the newton per square meter (N/m²), called the pascal (Pa). One pascal is a small pressure: a sheet of paper lying on a table presses down with about 1 Pa.

The same force makes a much bigger pressure on a small area. That is why a sharp knife cuts (its edge is very thin), why a drawing pin goes into a board easily, and why a porter’s namlo (head strap) is made wide, not thin.

Liquids and gases can flow, so together they are called fluids. A solid presses only downward on what it rests on, but a fluid presses on the bottom and on every wall of its container, and on every surface of anything placed in it.

Push a balloon under water and you can feel the water pushing it back up. Fill a balloon with hydrogen or helium and let it go: the air pushes it up, and it rises. Air gets thinner as you go higher, so the push of the air gets weaker; the balloon stops rising at the height where the upward push of the air just equals its weight. You will see why later in this unit.

glass, fullof watercardweight of the water:only about 1,000 Paair can push up with:about 100,000 Pathe atmosphere
Figure 8.1 An upturned glass full of water, closed with a card. The air can push up on the card far harder than the weight of the water presses down.

Two girls of the same weight stand on soft mud. One wears flat sandals; the other wears shoes with narrow high heels. Who sinks deeper, and why?

Pick an answer to see why.

Pressure in liquids and air

You met this in Grade 8; here it is again, because it explains so much of this unit.

The water at the bottom of a tank carries the weight of all the water above it. So the deeper you go, the greater the pressure. For a liquid of density ρ \rho (rho), at a depth h h :

P=hρg P = h\rho g

where g g = 9.8 m/s². Pressure in a liquid depends only on the depth and the density of the liquid, not on the shape of the container. And at any point it pushes equally in all directions: up, down and sideways.

shallowdeeperdeepestsurfacefarthestThe deeper the hole,the greater the pressure,so the faster the jet.
Figure 8.2 An open bottle of water with three holes at different depths. The deepest jet shoots out the hardest, because the pressure is greatest there.

The air around us is a fluid too. The atmosphere is an ocean of air about a hundred kilometers deep, and we live at its bottom. At sea level it presses with about 101,325 Pa, which is about 10 tonnes on every square meter. We don’t feel crushed because the fluids inside our bodies push outward just as hard. As you climb, there is less air above you, so the pressure falls: in Kathmandu it is about 85,000 Pa, and on the top of Everest only about a third of the sea-level pressure.

A long cylindrical craft with a small ball-shaped cabin underneath, hanging from a crane over the water
Figure 8.3 The bathyscaphe Trieste. The crew sat in the small steel ball under the big float. Photo: Unknown author, Public domain

In Figure 8.2, why does the water from the lowest hole travel farthest?

Pick an answer to see why.

Transmission of pressure

Why can a liquid pass on a push, while a solid can’t? Look at their particles (Figure 8.4). In a solid the particles are packed close and held in place: they can only vibrate. Push one side of a block of wood and the block just moves as a whole, or digs in where you push; the pressure does not spread out through it to all its surfaces. In a liquid and a gas the particles can move about, so a push on a fluid in a closed container spreads through all of it.

pushpushAir: the piston goes in.The particles are far apart and can be pushedcloser: a gas can be compressed.Water: the piston won’t move.The particles already touch and can’t getcloser: a liquid can’t be compressed.airwaterfingerfinger
Figure 8.4 Pushing the piston of a closed syringe. The particles of air are far apart, so the air can be squeezed; the particles of water are already touching, so the water can’t.

The particles of a liquid are already very close together, so pushing on it can’t move them closer, and its volume doesn’t change. A liquid in a closed vessel is incompressible, and so a pressure made at any point in it is passed on (transmitted) to every part of it, in all directions. When you squeeze a toothpaste tube at the bottom, the paste comes out at the top.

Gases are different. Their particles are far apart, so a push first squeezes the gas into a smaller volume. Pressure is transmitted through a gas too, but not as well as through a liquid. Squeeze a balloon in one place and it bulges everywhere else, but only once the air inside is already squeezed tight. That is why the hydraulic brakes of cars and motorbikes have a liquid in their pipes, not air. (Big buses and trucks often have air brakes, but those work differently: a compressor stores air at high pressure, and the driver’s pedal only lets it out.)

Why does toothpaste come out of the nozzle when you squeeze the bottom of the tube?

Pick an answer to see why.

Pascal’s law

squeezepinholes all around:water comes out of everyone, at right angles tothe surfacebag fullof water
Figure 8.5 A squeezed bag of water with pinholes. Water comes out of every hole, at right angles to the surface of the bag.

The French mathematician and scientist Blaise Pascal described this in 1653. It is known as Pascal’s law:

When pressure is applied at any point of a liquid in a closed container, it is transmitted equally in all directions, throughout the liquid, and acts at right angles to the walls of the container.

Checking Pascal’s law

Take a round vessel full of liquid with four pistons A, B, C and D, of cross-sectional areas a1 a_1 , a2 a_2 , a3 a_3 and a4 a_4 (Figure 8.6). Push piston A in with a force F1 F_1 . The other three pistons are pushed out. To stop them moving, you must push each one back with a force: F2 F_2 , F3 F_3 and F4 F_4 . When you measure them, you find

F1a1=F2a2=F3a3=F4a4 \frac{F_1}{a_1} = \frac{F_2}{a_2} = \frac{F_3}{a_3} = \frac{F_4}{a_4}

Each of these is a force divided by an area, which is a pressure. So the pressure is the same at every piston: the pressure made at one point of a liquid in a closed vessel is transmitted equally everywhere. A piston with twice the area needs twice the force to hold it back.

F₁A10 PaF₂B10 PaF₃C10 PaF₄D10 PaliquidF₁/a₁ = F₂/a₂= F₃/a₃ = F₄/a₄the same pressure at every piston
Figure 8.6 Checking Pascal’s law. A pressure of 10 Pa made at piston A appears as 10 Pa at every other piston, so a piston with a bigger area is pushed with a bigger force.

Applications of Pascal’s law

Pascal’s law is the idea behind hydraulic machines (from the Greek hydor, water): hydraulic brakes, hydraulic lifts, hydraulic jacks, hydraulic presses, and the arms of diggers and cranes.

Hydraulic machines

A hydraulic machine is a force multiplier based on Pascal’s law: a small force on a small piston becomes a large force on a large piston.

A yellow tracked excavator with its long arm and bucket lowered, beside a rocky hillside
Figure 8.7 An excavator at Rakhu Bhagawati in Myagdi, Nepal (often called a “JCB”, after one company that makes them). Each joint of its arm is moved by a hydraulic cylinder. Oil pushed through the hoses moves big pistons, so the driver’s small push on the levers becomes enough force to dig hard ground. Photo: Bijay Chaurasia, CC BY-SA 4.0

How a hydraulic machine is built and how it works

At least two cylinders of different cross-sectional areas are joined by a pipe and filled with a liquid, usually oil (Figure 8.8). Each cylinder has a piston that fits tightly, so no liquid leaks out. Let the small piston have area A1 A_1 and the large piston area A2 A_2 .

Push the small piston down with a force F1 F_1 (the input force). This makes a pressure in the liquid:

P1=F1A1 P_1 = \frac{F_1}{A_1}

The liquid can’t be compressed, so by Pascal’s law the same pressure reaches the large piston: P2=P1 P_2 = P_1 . There it pushes on a bigger area, so it makes a bigger force F2 F_2 (the output force):

F1A1=F2A2soF2=F1×A2A1 \frac{F_1}{A_1} = \frac{F_2}{A_2} \qquad \text{so} \qquad F_2 = F_1 \times \frac{A_2}{A_1}

Since A2 A_2 is bigger than A1 A_1 , the factor A2A1 \dfrac{A_2}{A_1} is always more than 1. If the large piston has twice the area of the small one, the force is doubled; with 50 times the area, the force is 50 times as big.

input force F₁(small)heavy loadoutput forceF₂ (large)area A₁area A₂oil: the same pressure P everywhereP = F₁ ÷ A₁F₂ = P × A₂
Figure 8.8 A hydraulic machine. The force F1 F_1 on the small piston makes a pressure P=F1/A1 P = F_1/A_1 ; the same pressure acting on the large piston makes the larger force F2=P×A2 F_2 = P \times A_2 .

Lift a car with one hand

Change the sizes of the two pistons and how hard you push. Can you lift the car? Watch how far the small piston has to move to raise the car by a few centimeters.

F₁ = 200 NF₂ = 45.0 kNoiloil tankone-way valve
Load
Pressure in the oil
637 kPa
Force multiplied by A2/A1
× 225
Force on the large piston
45.0 kN
Weight of the load
11.8 kN
10 cm strokes to lift it 10 cm
225

Press Push to pump the small piston.

Some hydraulic machines

Hydraulic machines come in many shapes and sizes, but each one has a small piston where you push and a large piston where the work is done.

a. Hydraulic lift

The dentist’s chair goes up when the dentist pumps a pedal: the pedal pushes a small piston, and the large piston under the seat lifts the patient. In a garage, a hydraulic car lift raises a whole car so the mechanic can work under it; there the small piston is pushed by compressed air from a compressor instead of a foot. Hydraulic lifts lift heavy loads easily.

b. Hydraulic brakes

In a car, the brake pedal pushes the piston of a small master cylinder. In a motorbike or scooter with disc brakes, the brake lever on the handle does the same. The master cylinder is joined by thin pipes, full of a special brake fluid, to a brake cylinder at each wheel, whose larger pistons press the brake pads (or brake shoes) against a disc or drum fixed to the wheel. A small push on the pedal becomes a large force on the pads, so a fast vehicle can be stopped in a few seconds. And because pressure is transmitted equally, the same pressure reaches the brake at every wheel at the same moment.

reservoir of brake fluidmaster cylinder(small piston)squeezebrake leverbrake hose, full of fluidcaliper with alarge pistonbrakepadsdisc (turns withthe wheel)
Figure 8.9 A disc brake, as on a motorbike. The lever pushes the small piston of the master cylinder; the pressure travels through the brake fluid to the larger piston in the caliper, which squeezes the pads against the spinning disc.

c. Hydraulic jack

A hydraulic jack lifts a truck, a bus or a car a little above the ground, for example to change a tyre. It has a pumping piston with a small area and a lifting piston with a large area, an oil reservoir, and two one-way valves (Figure 8.10):

  • The lower valve lets oil flow only from the pumping cylinder into the lifting cylinder.
  • The upper valve lets oil flow only from the reservoir into the pumping cylinder.

First the release valve is closed tightly. Then:

  1. Push the lever down. The pumping piston pushes oil out: the upper valve shuts and the lower valve opens. Oil is forced into the lifting cylinder and the load rises a little.
  2. Pull the lever up. The high pressure under the load shuts the lower valve, so the load can’t come back down. The upper valve opens, and fresh oil is sucked from the reservoir into the pumping cylinder.
  3. Repeat. Each stroke lifts the load a little more, until it is high enough.

To lower the load, open the release valve: the oil flows from the lifting cylinder back into the reservoir.

loadpush down,pull upram (large piston)liftingcylinderpumping piston(small)lower valveupper valveoilreservoirrelease valvelever
Figure 8.10 A hydraulic jack. Pushing the lever down forces oil through the lower valve into the lifting cylinder; pulling it up draws fresh oil from the reservoir through the upper valve.

d. Hydraulic press

In a hydraulic press, the thing to be pressed is placed between the large piston and a rigid plate fixed above it. A small force on the small piston becomes a huge force pressing up. Presses are used to fit tight parts of vehicles together, to bend metal sheets or punch holes in them, and to pack paper, cotton or straw into tight bales.

In a hydraulic press, the large piston has 30 times the area of the small one. You push the small piston with 50 N. What force does the large piston exert?

Pick an answer to see why.

Why is the liquid in a hydraulic machine not replaced by air?

Pick an answer to see why.

Upthrust

The water pushes the bottle up. The total upward force that a fluid exerts on an object in it is called upthrust (or buoyant force). Its SI unit is the newton (N).

Upthrust is the upward force exerted by a fluid (a liquid or a gas) on an object that is partly or completely immersed in it.

Every object in a fluid has two forces on it, in opposite directions (Figure 8.11):

  • its weight (W W ), the pull of gravity, downward;
  • the upthrust (U U ) of the fluid, upward.

The upthrust works against the weight and makes it partly or completely “disappear”. What happens depends on which is bigger:

Compare What happens Example
W>U W > U the object sinks (or falls) the bottle let go in the air
W=U W = U the object floats (or stays where it is) the bottle floating on water
W<U W < U the object rises the bottle pushed under water and let go
WUin airW > U: it fallsWUfloatingW = U: it floatsWUpushed underU > W: it risesW = weight (down)U = upthrust (up)
Figure 8.11 The two forces on a bottle. In the air, its weight is much bigger than the tiny upthrust of the air, so it falls. Floating, the upthrust equals the weight. Pushed under, the upthrust is bigger than the weight, so it rises when let go.

Air gives upthrust too, but air is about 800 times less dense than water, so its upthrust on a bottle or a bucket is tiny, and we usually ignore it. On a big balloon it matters, as you will see.

Why there is upthrust

Think of a cube held under water (Figure 8.12). The water presses on every face of it, at right angles to the face.

  • The forces on the left and right faces are equal and opposite, so they cancel. So do the forces on the front and back faces.
  • But the bottom face is deeper than the top face, and pressure grows with depth. So the water pushes up on the bottom face harder than it pushes down on the top face.

Subtract the downward force on the top from the upward force on the bottom, and what’s left is a force upward. That is the upthrust. It is always upward, because “deeper” is always below.

water surfaceh₁h₂small pushdown on the topsideways pushescancelbigger push upon the bottom(it is deeper)upthrust= the difference
Figure 8.12 The water presses on every face of a cube at right angles. The sideways forces cancel; the push up on the bottom face is bigger than the push down on the top face, because the bottom is deeper.

Measuring upthrust

3 Nin air2 Nin water
Figure 8.13 A stone weighs 3 N in air but only 2 N in water. The difference, 1 N, is the upthrust of the water on it.

The weight of an object measured in air (W1 W_1 ) is its real weight. The weight it seems to have in a liquid (W2 W_2 ) is its apparent weight. The stone has not lost any mass; the upthrust just takes part of the load off the spring. So

Upthrust (U)=real weight (W1)−apparent weight (W2) \text{Upthrust } (U) = \text{real weight } (W_1) - \text{apparent weight } (W_2)

What decides how big the upthrust is

a. The density of the liquid

The upthrust on an object is directly proportional to the density of the liquid: the denser the liquid, the bigger the upthrust on the same object.

So an iron ball sinks in water but floats on mercury, which is 13.6 times as dense as water. A ship floats a little higher in seawater than in river water, because seawater is denser. And it is easier to swim in the sea than in a river or a pool.

b. The volume of liquid displaced

When an object goes into a liquid, it pushes the liquid out of the way: it displaces it. The part of the object under the surface takes up space that the liquid filled before.

Hang a metal cylinder from a spring balance and lower it into water, little by little (Figure 8.14). As more of it goes under, it displaces more water, and the balance reading falls. Once it is completely under, the reading stays the same, however deep you take it.

5 Nin air4 N⅓ under3 N⅔ under2 Nall under2 Ndeeper
Figure 8.14 Lowering a cylinder into water. The more of it is under water, the more water it displaces and the bigger the upthrust. Once it is completely under, the upthrust stops growing.

The upthrust on an object is directly proportional to the volume of liquid it displaces.

  • Two cubes of the same volume but different weights (say one of iron and one of aluminium), completely under water, displace the same volume of water, so they get the same upthrust.
  • A big closed plastic bottle is harder to push under than a small one: it displaces more water, so it gets more upthrust.
  • In the same way, a big helium balloon gets more upthrust from the air than a small one.

Weigh it in different liquids

Lower the block into the liquid and watch the spring balance, the upthrust, and the liquid that overflows into the little beaker. Then change the liquid.

0 N1 N2 N3 Noverflow0 N0.5 N1 Nall underlowered further →upthrust
Liquid
Real weight
2.65 N
Balance reads
2.65 N
Upthrust
0.00 N
Liquid displaced
0 cm³ = 0.00 N

A stone is weighed while hanging in air, in water and in salt water. Where does the balance show the smallest reading?

Pick an answer to see why.

A small iron cube and a large wooden cube are both held completely under water. Which gets more upthrust?

Pick an answer to see why.

Archimedes’ principle

How big, exactly, is the upthrust? Here is the experiment that answers it.

10 Nin air6 Nin water, in a eureka canwater pushed out(displaced): 4 Nupthrust= 10 N − 6 N = 4 N= weight of the water displaced
Figure 8.15 A solid weighs 10 N in air and 6 N in water, so the upthrust on it is 4 N. The water it pushes out of the eureka can also weighs 4 N.

This was first stated by Archimedes, a Greek mathematician and engineer born in 287 BC in Syracuse, on the island of Sicily.

Archimedes’ principle: when an object is partly or completely immersed in a fluid, the upthrust on it is equal to the weight of the fluid it displaces.

It is true for all fluids, liquids and gases alike. In symbols:

U=weight of fluid displaced=mg U = \text{weight of fluid displaced} = mg

The mass of the fluid displaced is its volume times its density, m=Vρ m = V\rho . So

U=Vρg U = V\rho g

where V V is the volume of fluid displaced (the volume of the part of the object under the surface), ρ \rho is the density of the fluid, and g g is the acceleration due to gravity. This one formula holds both factors you found above: the upthrust grows with the volume displaced and with the density of the fluid.

So whether an object floats or sinks depends on its weight and on the upthrust, which depends on the volume of liquid it can displace.

Relative density

Part (d) of that example is a neat trick: with just a spring balance and a bowl of water, you can find the density of a stone of any shape. The ratio of the density of a substance to the density of water is called its relative density:

relative density=density of the substancedensity of water=W1W1−W2 \text{relative density} = \frac{\text{density of the substance}}{\text{density of water}} = \frac{W_1}{W_1 - W_2}

The second form comes straight from Archimedes’ principle: W1−W2 W_1 - W_2 is the weight of a volume of water equal to the volume of the object. Relative density is a ratio of two densities, so it has no unit. For the stone above it is 4.91.47≈3.3 \dfrac{4.9}{1.47} \approx 3.3 : the stone is 3.3 times as dense as water.

A block weighs 12 N in air and 9 N in water. What is the weight of the water it displaces?

Pick an answer to see why.

Flotation

A simple rule works for a solid lump of one material: if the object is less dense than the liquid, it floats; if it is denser, it sinks. Wood (about 600 kg/m³) floats on water (1000 kg/m³); a stone (about 2,500 kg/m³) sinks. But comparing densities is not the whole story, as this activity shows.

Aluminium has a density of 2,700 kg/m³, 2.7 times that of water, so you’d expect it to sink, and the ball does. But the tray floats. So whether an object floats or sinks depends not only on the density of its material but also on its shape, which decides how much water it can displace. What really counts is the average density of the whole object, including the air inside it. The tray, with the air it holds, is on average less dense than water.

The weight and the upthrust act in exactly opposite directions. When the upthrust cancels the weight, the resultant force is zero, and the object floats.

A floating object may be partly or completely under the surface. Only the part under the surface displaces liquid. For an object to float, the weight of the liquid it displaces must equal its own weight. This is the law of flotation:

A floating object displaces a weight of liquid equal to its own weight.

weight of the floating object=weight of liquid displaced \text{weight of the floating object} = \text{weight of liquid displaced}

Float or sink?

Choose an object and a liquid. The block settles where its weight equals the upthrust, so you can see how much of it is under the surface. Try the same block in fresh water, in seawater and in the Dead Sea.

weightupthrustpart under thesurface92%block ÷ liquiddensity =917 ÷ 1,000= 0.92
Block
Liquid
Block’s density
917 kg/m³
Liquid’s density
1,000 kg/m³
Result
Floats

It floats, but only just: most of it has to go under before the upthrust equals its weight.

a. Floating in liquids

Ships and boats

A block of iron sinks: the water it can displace (its own volume of water) weighs far less than the block. Beat the same iron into a bowl and it floats: the bowl displaces a much bigger volume of water, enough to weigh as much as the bowl (Figure 8.16). A ship is the same idea on a huge scale. Its hull is made wide, long and deep, so that it can displace enough water to give an upthrust equal to its weight. A ship of 50,000 tonnes must sit deep enough to push aside 50,000 tonnes of water. So iron sinks, but a ship of iron floats.

block: sinksdisplaces only its ownsmall volume of waterbowl: floatsits shape displaces enoughwater to equal its weightship: floatsa wide, long, deep hulldisplaces its weight of waterwater displaced
Figure 8.16 The same amount of iron, three shapes. As a solid block it displaces little water and sinks. As a bowl, or as the hull of a ship, it displaces enough water to float.

A boat works the same way. When people climb in, the boat sinks a little deeper, displaces more water, and so gets more upthrust, just enough to carry the extra weight. But once the water reaches the top edge of the boat, it can’t displace any more. Add more weight and the upthrust can’t grow to match it, so water pours in and the boat sinks. And a hole in the bottom lets water in, which adds weight and takes away the air that made the boat’s average density low: the boat sinks.

Submarines and fish

A submarine can float on the surface or travel deep under it. It has large ballast tanks. To dive, it lets seawater into the tanks: its weight increases, becomes more than the upthrust, and it goes down. To come up, compressed air blows the water out of the tanks: its weight decreases, the upthrust wins, and it rises to the surface. With the tanks partly full, it can hang still at any depth.

water let in: heavierair blows water out: lighterDiving: weight > upthrustSurfacing: weight < upthrustballasttanks
Figure 8.17 A submarine. Letting water into the ballast tanks makes it heavier, so it dives; blowing the water out with compressed air makes it lighter, so it rises.

Many fish use the same trick. They have a gas-filled bag in their bodies, the swim bladder. Filling it with more gas makes the body bigger, so it displaces more water and gets more upthrust: the fish rises. Letting gas out makes the body smaller, so the upthrust falls and the fish goes deeper. (Strictly, the submarine changes its weight and keeps its volume, while the fish changes its volume and keeps its weight. Both change the balance between weight and upthrust.)

The hydrometer and the lactometer

A hydrometer measures the relative density of a liquid. It is a sealed glass tube with a wide bulb at the bottom, weighted with lead shot or mercury so that it floats upright, and a thin stem marked with a scale. It sinks until it displaces its own weight of liquid. In a dense liquid, a small volume is enough, so it floats high; in a less dense liquid it sinks deeper. The reading at the surface gives the relative density, so the numbers on the stem get bigger towards the bottom.

less dense liquidit sinks deeperreading: lowdenser liquidit floats higherreading: highweighted bulb(lead shot keepsit upright)stem with a scale:bigger numberslower down
Figure 8.18 The same hydrometer in a less dense and a denser liquid. In the denser liquid it needs to displace less volume to get the same upthrust, so it floats higher.

A lactometer is a hydrometer made for milk. Pure cow’s milk is a little denser than water (relative density about 1.028 to 1.034). If water has been mixed into the milk, its density is lower, and the lactometer sinks deeper than it should. Dairies and milk collection centers check milk this way.

A glass hydrometer: a thin tube with a scale, weighted at the bottom with a bulb of red-coated shot
Figure 8.19 A hydrometer. The weighted bulb at the bottom keeps it upright; the scale is read where the liquid’s surface meets the stem. Photo: Jacek Halicki, CC BY-SA 4.0

A lactometer floats lower in one sample of milk than in another. What does this tell you about the first sample?

Pick an answer to see why.

b. Floating in the air

Objects can float in gases just as in liquids. The air gives an upthrust equal to the weight of the air the object displaces. Air’s density is so small (about 1.2 kg/m³) that the upthrust matters only for objects that are very light for their size.

A balloon filled with helium or hydrogen is such an object. The air it displaces weighs more than the balloon and its gas, so the upthrust is greater than its weight, and it rises. But the air gets thinner as the balloon climbs, so the upthrust gets smaller. At some height the upthrust equals the weight, and the balloon floats there. Also, as the air pressure outside falls, the gas inside pushes the balloon’s skin outward and the balloon swells; a party balloon keeps growing until it bursts.

Hot-air balloons fly in the same way, but they use hot air instead of a light gas. When air is heated, it expands, so its density falls. The air inside the huge balloon is hot and less dense than the cool air around it. The balloon displaces a very large volume of cool air, so the upthrust becomes greater than the total weight of the balloon, its hot air, the basket and the people, and the balloon rises. As it climbs into thinner air, the upthrust falls, and at some height it equals the weight: the balloon floats there.

The pilot steers up and down with a burner. Turn the flame on: the air inside gets hotter and less dense, the balloon gets lighter, and it rises. Turn it off: the air inside cools, its density increases, and when the weight becomes greater than the upthrust, the balloon sinks slowly back to the ground.

Looking up into a hot-air balloon from below, with a big yellow flame from the burner heating the air inside
Figure 8.20 The burner of a hot-air balloon heats the air inside it. Hotter air is less dense, so the balloon rises. Photo: 5snake5, CC0

A hot-air balloon is floating at a steady height. The pilot turns off the burner. What happens, and why?

Pick an answer to see why.

Project work

Exercise

1. Choose the correct option

a. On which law or principle is a lactometer based?

Pick an answer to see why.

b. What is the condition for a hydrogen balloon to fly upwards in the air?

Pick an answer to see why.

c. In a hydraulic machine, the cross-sectional area of the larger piston is twice that of the smaller piston. Which weights on the smaller piston (W1 W_1 ) and the larger piston (W2 W_2 ) keep the machine balanced?

Pick an answer to see why.

d. An object hung from a spring balance weighs W1 W_1 in air, W2 W_2 in water and W3 W_3 in glycerine. Which order is correct, from smallest to largest?

Pick an answer to see why.

e. When a ship sails from the sea into a river, it sinks deeper into the water. Why?

Pick an answer to see why.

f. A hand pushes a ball down into water. Which statement is correct?

Pick an answer to see why.

g. Three cubes made of different materials get the same upthrust when they are put in water. Which quantity is the same for all three?

Pick an answer to see why.

h.

What is the upthrust on the object in the figure when it is put in the liquid?

4 Nin air1 Nin water, in a eureka canwater pushed out(displaced)
Figure 8.21 The object weighs 4 N in air and 1 N when it is in the liquid.

Choose one:

Pick an answer to see why.

2. Differentiate between

a.

Pressure and upthrust

Answer
Pressure Upthrust
The thrust (force at right angles) acting on a unit area. The total upward force a fluid exerts on an object in it.
P=F/A P = F/A ; in a liquid, P=hρg P = h\rho g . U=Vρg U = V\rho g = weight of fluid displaced.
SI unit: pascal (Pa = N/m²). SI unit: newton (N).
Acts in all directions, at right angles to every surface. Acts only upward.
Increases with depth in a fluid. Does not change with depth once the object is completely immersed.
b.

The reason a steel pin sinks in water and a steel plate floats

Answer
Steel pin Steel plate (dish-shaped)
Small and solid: it displaces only its own small volume of water. Its wide, hollow shape displaces a large volume of water.
The upthrust is less than its weight, so it sinks. It displaces water weighing as much as itself before it is completely under, so upthrust = weight, and it floats.
Its average density is that of steel, about 7,800 kg/m³, more than water. Its average density (steel plus the air it holds) is less than water.
c.

The processes of a hot-air balloon rising and sinking in the air

Answer
Rising Sinking
The burner heats the air inside the balloon. The burner is turned off, and the air inside cools.
The hot air expands; its density decreases. The air contracts; its density increases.
The total weight becomes less than the upthrust (the weight of the cool air displaced). The total weight becomes more than the upthrust.
There is a net upward force, so the balloon rises. There is a net downward force, so the balloon sinks.

3. Give reasons

a.

A special type of oil is used in hydraulic brakes.

Answer

The brake fluid must pass on the pressure from the pedal or lever to the brake pads fully and at once, so it must be a liquid that can’t be compressed (air or any gas would be squeezed instead, and the brakes would fail). It must also have a high boiling point, because braking makes the brakes very hot, and a bubble of vapor would act like air; a low freezing point, so it works in cold weather; and it must not damage the rubber seals or rust the metal parts. Ordinary water or oil can’t do all of this, so a special brake fluid is used.

b.

A wooden cork pushed under the surface of water with a finger comes back to the surface when the finger is removed.

Answer

Under the water, the cork displaces its whole volume of water. Cork is much less dense than water, so the weight of that water, the upthrust, is much greater than the cork’s weight. With the finger gone there is a net upward force, so the cork rises until only part of it is under water and the upthrust equals its weight.

c.

We feel lighter while floating in water.

Answer

The water gives our body an upthrust equal to the weight of water we displace. While floating, the upthrust equals our whole weight, so our muscles and the ground don’t have to hold us up. Our apparent weight is almost zero, so we feel light. (Our mass and real weight haven’t changed.)

d.

When a stone is lifted out of water, it feels heavier as it comes out.

Answer

Under water, the upthrust of the water holds up part of the stone’s weight, so we only lift its apparent weight. In the air, the upthrust is almost zero, so we must lift its full, real weight. Its weight hasn’t changed; we just lost the water’s help.

e.

It is easier to float in the Dead Sea than in a swimming pool. (The density of water in the Dead Sea is 1,240 kg/m³.)

Answer

The Dead Sea is so salty that its water is 1.24 times as dense as pool water. A body must displace its own weight of water to float. In the denser Dead Sea water, a smaller volume is enough, so the body floats with much of it above the surface. A person whose average density is about 1,000 kg/m³ floats with only about 1000/1240≈81% 1000/1240 \approx 81\% of the body under the water there, compared with nearly all of it in a pool. People can lie on their back and read a newspaper.

A man floating on his back in the Dead Sea, holding up a newspaper to read, with his feet sticking out of the water
Figure 8.22 Reading the newspaper while floating in the Dead Sea. The very salty water gives so much upthrust that the body floats high. Photo: Pete, CC BY-SA 3.0
f.

If more passengers climb into a boat than its maximum capacity, the boat is likely to sink.

Answer

Each passenger makes the boat sink a little deeper, so it displaces more water and gets enough extra upthrust to carry them. But once the water reaches the top edge of the boat, it can’t displace any more water, so the upthrust can’t grow any more. Extra weight beyond that is more than the greatest upthrust the boat can get; water comes in over the edge and the boat sinks. (In Nepal, overloaded boats and ferries on rivers and lakes have capsized in this way. Never get into a boat that is already full, and wear a life jacket.)

4. Answer these questions

a.

State Pascal’s law.

Answer

When pressure is applied at any point of a liquid enclosed in a container, it is transmitted equally in all directions throughout the liquid, and acts at right angles to the walls of the container.

b.

Write any two applications of Pascal’s law in daily life.

Answer

Any two of: hydraulic brakes in cars and motorbikes; the hydraulic jack used to lift vehicles; hydraulic lifts (the dentist’s chair, garage car lifts); the hydraulic press; excavators (diggers) and cranes; a barber’s chair that pumps up.

c.

What is a hydraulic machine?

Answer

A hydraulic machine is a force-multiplying device based on Pascal’s law. Two cylinders of different areas, with tightly fitting pistons, are joined and filled with a liquid. A small force on the small piston makes a pressure that is transmitted through the liquid to the large piston, where it produces a larger force: F2=F1×A2/A1 F_2 = F_1 \times A_2/A_1 . Examples: the hydraulic jack, brake, lift and press.

d.

State Archimedes’ principle.

Answer

When an object is partly or completely immersed in a fluid, it experiences an upthrust equal to the weight of the fluid it displaces.

e.

What is upthrust?

Answer

Upthrust is the upward force exerted by a fluid on an object that is partly or completely immersed in it. It is equal to the weight of the fluid displaced (U=Vρg U = V\rho g ), and its SI unit is the newton.

f.

Name the forces acting on a floating object, and give their directions.

Answer

Two forces: the weight of the object (the pull of gravity), acting vertically downward, and the upthrust of the liquid, acting vertically upward. For a floating object they are equal in size, so the resultant force is zero.

g.

State the law of flotation.

Answer

A floating object displaces liquid whose weight is equal to its own weight. (Weight of the floating object = weight of the liquid displaced.)

h.

Write any two applications of Archimedes’ principle.

Answer

Any two of: designing ships and boats so they displace enough water to float; submarines, which sink and rise by filling and emptying ballast tanks; the hydrometer, which measures the relative density of liquids; the lactometer, which tests whether milk has been watered down; hot-air and helium balloons; finding the density or purity of an object of any shape by weighing it in air and in water.

i.

Using materials you can find, describe one way to show upthrust in a liquid and one way to show it in a gas.

Answer

In a liquid: push an empty plastic bottle, its cap screwed on tight, down into a bucket of water. You feel it pushing back up, and when you let go it pops up to the surface. (Or hang a stone from a spring balance and weigh it in air, then in water: it weighs less in water, and the difference is the upthrust.)

In a gas: let go of a balloon filled with helium or hydrogen: it rises, because the air’s upthrust on it is more than its weight. (Or blow hot air into the mouth of a light paper bag from below, with a hair dryer: once the air inside is less dense, the bag rises.)

j.

Explain, with a figure, why there is upthrust.

Answer

Draw a cube held under water, with arrows at right angles to each face, as in Figure 8.12. Then explain:

  1. A liquid presses on every surface of an object in it, at right angles to the surface.
  2. The forces on the opposite side faces (left–right, front–back) are equal and opposite, so they cancel.
  3. Pressure increases with depth (P=hρg P = h\rho g ). The bottom face is deeper than the top face, so the upward force on the bottom is greater than the downward force on the top.
  4. The difference between these two forces is a net upward force: the upthrust. For a cube of volume V V , it works out as Vρg V\rho g , the weight of the liquid displaced.
k.

A stone dropped into water sinks. Is that because there is no upthrust on it?

Answer

No. The water does give the stone an upthrust, equal to the weight of the water it displaces (you can see it: the stone weighs less on a spring balance when it is in the water). The stone sinks because it is denser than water, so its weight is greater than the upthrust. The upthrust only slows the stone down; it can’t stop it.

l.

A person is trying to lift a stone of 500 N by putting it on the smaller piston of a hydraulic machine and pushing on the larger piston. What would you suggest so that the load can be lifted easily? Explain, with a figure, how a hydraulic machine increases a force.

Answer

Suggestion: put the stone on the larger piston and push on the smaller piston. The way it is now, the machine works backwards: to lift 500 N on the small piston, the push on the large piston must be 500 N × A2/A1 A_2/A_1 , many times bigger than the stone’s weight.
How the force is increased (draw Figure 8.8): a force F1 F_1 on the small piston of area A1 A_1 makes a pressure P=F1/A1 P = F_1/A_1 in the liquid. By Pascal’s law, this pressure is transmitted equally through the liquid to the large piston of area A2 A_2 , where it makes a force F2=P×A2=F1×A2/A1 F_2 = P \times A_2 = F_1 \times A_2/A_1 . Since A2>A1 A_2 > A_1 , F2>F1 F_2 > F_1 . For example, if A2 A_2 is 10 times A1 A_1 , a push of 50 N on the small piston lifts the 500 N stone on the large one.

m.

“A substance denser than a liquid sinks in it.” Is this statement always true? Justify with an example.

Answer

No. It is true for a solid lump of the substance, but not for an object shaped to hold air. Iron (7,800 kg/m³) is much denser than water, yet a ship made of iron floats; aluminium foil (2,700 kg/m³) sinks as a crumpled ball but floats as a tray. A hollow, wide shape displaces a large volume of water, enough to give an upthrust equal to its weight. What decides floating is the average density of the whole object, including the air inside it, compared with the density of the liquid.

n.

Two balloons that look identical are filled, one with air and the other with hydrogen. What difference will you notice when they are let go in the air? Explain why.

Answer

The hydrogen balloon rises; the air balloon falls to the ground. Both displace the same volume of air, so both get the same upthrust. But the air balloon contains air (slightly squeezed, so a little denser than the air outside) plus the rubber, so its weight is more than the upthrust. Hydrogen is about 14 times less dense than air, so the hydrogen balloon’s total weight is less than the upthrust, and it rises.

o.

An object is floating just below the surface of water. If more and more salt is dissolved in the water, what will happen to the object? Explain why.

Answer

The object will rise, and then float with part of it above the surface, rising higher as more salt is dissolved. Dissolving salt increases the density of the water. The object, completely under, now displaces water of greater density, so the upthrust (Vρg V\rho g ) becomes greater than its weight and it moves up. It comes to rest when only enough of it is under the surface to displace its own weight of the denser water, and the denser the water, the less of it needs to be under.

p.

What does the weighing machine read in each picture of (a) and (b)? Explain why.

20 N5 N?8 N?(a)30 N5 N?8 N?(b)a beaker that is not fulla beaker full to the brim
Figure 8.23
  • a.A beaker of water that is not full weighs 20 N; blocks of 5 N and 8 N are floated on it.
  • b.A beaker filled to the brim weighs 30 N; the same blocks are floated on it, and water overflows.
Answer
  • a.25 N with the 5 N block, and 28 N with the 8 N block. The blocks float, so the water holds up their whole weight, and the water rests on the machine. No water leaves the beaker, so the machine reads the water plus the block: 20 + 5 = 25 N and 20 + 8 = 28 N.
  • b.30 N both times. By the law of flotation, a floating block displaces its own weight of water. The beaker was full, so that water spills out over the edge. The 5 N block pushes out 5 N of water, and the 8 N block pushes out 8 N of water, so the weight on the machine stays 30 N.
q.

When a person puts a lactometer into some milk, the whole of its narrow stem sinks into the milk. What can you conclude?

Answer

The lactometer sinks deeper in a less dense liquid. Since even its whole stem went under, the milk is much less dense than pure milk (relative density about 1.03), so the milk has very likely been mixed with a lot of water. It is not pure; a milk collection center would reject it.

5. Solve these problems

a.

The figure shows a model of a hydraulic machine made from two syringes. How much force must be applied through syringe B to balance the 20 N force on piston A?

20 N?syringe A: piston area 0.5 cm²syringe B: piston area 5 cm²plastic tube full of oil
Figure 8.24 Piston A (area 0.5 cm²) is pushed with 20 N. The syringes are joined by a plastic tube full of oil. Piston B has an area of 5 cm².
Answer

Given: FA F_A = 20 N, AA A_A = 0.5 cm², AB A_B = 5 cm². Find FB F_B .
By Pascal’s law, the pressure is the same at both pistons:
FAAA=FBAB⇒FB=FA×ABAA=20 N×50.5=200 N \frac{F_A}{A_A} = \frac{F_B}{A_B} \quad\Rightarrow\quad F_B = F_A \times \frac{A_B}{A_A} = 20\ \text{N} \times \frac{5}{0.5} = 200\ \text{N}
(The areas can stay in cm² because only their ratio is used.) A force of 200 N is needed on piston B.

b.

A pressure of 30,000 Pa is produced in the liquid of a hydraulic lift. If the cross-sectional area of the piston that lifts the load is 0.1 m², how much load can it lift?

Answer

Given: P P = 30,000 Pa, A A = 0.1 m². Find F F .
F=P×A=30,000 Pa×0.1 m2=3000 N F = P \times A = 30{,}000\ \text{Pa} \times 0.1\ \text{m}^2 = 3000\ \text{N}
It can lift a load of 3,000 N, a mass of about 3000/9.8≈306 3000/9.8 \approx 306 kg.

c.

Find the upthrust on the object in situations b and c of the figure. Why are the two upthrusts different?

20 Na14 Nb10 Nc
Figure 8.25 The spring balance reads 20 N with the object in air (a), 14 N with it partly under water (b), and 10 N with it completely under water (c).
Answer

Real weight W1 W_1 = 20 N.

  • b.U=20−14=6 N U = 20 - 14 = 6\ \text{N}
  • c.U=20−10=10 N U = 20 - 10 = 10\ \text{N}

Why different: in (b) only part of the object is under water (6/10, three-fifths of it), so it displaces less water; in (c) it is completely under and displaces more. Upthrust equals the weight of water displaced, so it is bigger in (c). The water collected in the small beaker in (c) weighs 10 N, and in (b) 6 N.