SEE Model Paper 6
Full marks: 75Time: 3 hours
All questions are compulsory.
Write your answers on paper first. Then open each answer and its marking scheme, and give yourself one mark for each point you got. In multiple choice, your first choice counts.
Section A
10 × 1 = 101. Choose the correct option for each of the following questions.
Before cable and dish TV, many homes in Nepal watched TV through an antenna on the roof. Antenna TV gave the poorest picture and sound of the three ways. Why?
Pick an answer to see why.
Which of the following animals is placed in the phylum Platyhelminthes?
Pick an answer to see why.
The body cells of a plant have 24 chromosomes. How many chromosomes will each of its gametes have?
Pick an answer to see why.
After a big volcanic eruption, the Earth’s surface is often a little cooler for a year or two. Why?
Pick an answer to see why.
A cricket ball is thrown straight up. At the highest point of its path, what are its velocity and its acceleration?
Pick an answer to see why.
A water tank on a roof is 2.5 m deep and full. What is the pressure of the water at its bottom? (Density of water = 1,000 kg/m³, g = 9.8 m/s²)
Pick an answer to see why.
A big tank holds 500 kg of water at 40 °C, and a cup holds 0.2 kg of tea at 80 °C. Which of the following is true?
Pick an answer to see why.
Lack of which vitamin in the body is one of the main causes of night blindness?
Pick an answer to see why.
A galaxy 30 Mpc away is moving away from us at 2,190 km/s. By Hubble’s law, how fast is a galaxy 90 Mpc away moving away from us?
Pick an answer to see why.
Milk kept in a refrigerator stays fresh for much longer than milk left in a warm kitchen. Which factor affecting the rate of reaction does this show?
Pick an answer to see why.
Section B
9 × 1 = 92. Write very short answers to the following questions.
Write the name of the device that turns the binary numbers of a digital signal back into a smoothly changing voltage for a loudspeaker.
Answer
A digital-to-analog converter (DAC).
Marking scheme
- Digital-to-analog converter (DAC).
A bat flies with wings, but it is placed in the class Mammalia, not in Aves. Why?
Answer
Because its body is covered with hair, not feathers, and it gives birth to its young and feeds them milk from its mammary glands. Its wings are thin skin stretched between very long fingers.
Marking scheme
- It has hair (not feathers) and mammary glands (feeds its young on milk; gives birth to young).
Which type of RNA brings the right amino acids to the ribosome, one by one?
Answer
Transfer RNA (tRNA).
Marking scheme
- Transfer RNA (tRNA).
A porter’s namlo (head strap) is made wide, not thin. Why?
Answer
A wide strap spreads the load’s weight over a larger area of the forehead, so the pressure on it is smaller and it hurts less.
Marking scheme
- A larger area gives less pressure for the same weight (P = F/A).
The normal temperature of the human body is 37 °C. What is it on the kelvin scale?
Answer
Marking scheme
- 310 K.
Looking straight at one end of a solenoid, Asmita sees the current going round it clockwise. Which pole is that end of the solenoid?
Answer
A south pole. With the right-hand grip rule, the fingers curl clockwise as seen from that end, so the thumb points away from her, to the far end: the far end is the north pole. (Clockwise current at an end means S; anticlockwise means N.)
Marking scheme
- South pole.
In Activity 12.3, the dots drawn on a balloon move apart as it is blown up, although none of them crawls across the rubber. What does this show about the galaxies of the universe?
Answer
The galaxies are not flying apart through space: space itself is expanding, like the rubber between the dots, and carries them apart. (From any galaxy, all the others seem to move away; there is no center.)
Marking scheme
- Space itself expands and carries the galaxies apart (so every galaxy moves away from every other).
A bottle of soft drink fizzes when its cap is opened. Why?
Answer
Carbon dioxide is dissolved in the drink under high pressure. When the cap is opened, the pressure drops, the gas can no longer stay dissolved, and it escapes as bubbles.
Marking scheme
- CO₂ dissolved under high pressure escapes as bubbles when the pressure drops on opening.
Rabin’s uncle says that methylated spirit is safe to drink, because it is mostly ethanol. Is he right? Give a reason.
Answer
No. Methylated spirit is ethanol with methanol added precisely so that nobody drinks it. Methanol is a poison: the body turns it into formaldehyde and formic acid, and as little as 10 mL can cause permanent blindness, and about 30 mL can kill.
Marking scheme
- No: it contains methanol, a poison that can cause blindness or death.
Section C
14 × 2 = 28Write short answers to the following questions.
Rita made a circuit of a 5 V d.c. supply, a switch and a bulb (Activity 13.1). She switched it on or off once every second and recorded the potential difference across the bulb.
| Time (s) | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
|---|---|---|---|---|---|---|---|---|
| Potential difference (V) | 5 | 0 | 5 | 5 | 0 | 0 | 5 | 0 |
- i.Write the signal she made as a string of bits.
- ii.If she kept the switch on and used the a.c. mains instead of the d.c. supply, how would the graph of voltage against time look, and what kind of signal would it be?
Answer
- i.5 V is a high signal, 1, and 0 V a low signal, 0, so the signal is 10110010 (eight bits, one byte).
- ii.The voltage would rise and fall smoothly through every value between −V and +V, a wave with no flat steps. It would be an analog signal; her switched d.c. signal, with only two values that it jumps between (a square wave), is digital.
Marking scheme
- i. 10110010.
- ii. A smooth wave through every value between −V and +V: an analog signal.
Kamala pulled up two plants from her garden. Plant X had long, narrow leaves with veins running side by side and a bunch of thin roots growing from the base of the stem. Plant Y had broad leaves with a net of veins and one thick main root with branches.
- i.Which plant is a monocot and which is a dicot?
- ii.Write one feature of the seed or the flower by which she could check each answer.
Answer
- i.X is a monocot (parallel venation, fibrous roots). Y is a dicot (reticulate venation, taproot).
- ii.Any one for each: X’s seed has one cotyledon, or the parts of its flower are in threes; Y’s seed has two cotyledons (it splits into two halves), or the parts of its flower are in fours or fives.
Marking scheme
- i. X monocot, Y dicot.
- ii. One correct seed or flower feature for each (one cotyledon or parts in threes; two cotyledons or parts in fours or fives).
Write any two reasons why Mendel chose the garden pea for his experiments.
Answer
Any two:
- a.Its flowers stay closed and pollinate themselves, so the plants stay pure; they can also be cross-pollinated by hand.
- b.Its life cycle is short, so many generations can be studied quickly.
- c.It has many clear pairs of contrasting characters (tall or dwarf, round or wrinkled seed).
- d.Each plant gives many seeds, so there are many offspring to count.
- e.It is easy to grow.
Marking scheme
- One correct reason.
- A second correct reason.
A doctor counts 47 chromosomes in the body cells of a newborn baby, with three copies of chromosome 21 instead of two. The baby has Down syndrome.
- i.What went wrong, and in which kind of cell division?
- ii.Meiosis keeps the number of chromosomes the same from one generation to the next. What would happen to the number in human body cells if gametes were made by mitosis instead?
Answer
- i.When one of the parents’ gametes was made by meiosis, the two chromosomes of pair 21 failed to separate, so that gamete got an extra chromosome 21 (24 instead of 23). At fertilization, 24 + 23 gave a zygote with 47.
- ii.The gametes would have 46 chromosomes, like body cells, so the zygote would have 46 + 46 = 92, and the number would double every generation (46, 92, 184 …).
Marking scheme
- i. In meiosis the pair of chromosome 21 failed to separate, so a gamete had an extra one.
- ii. Gametes would have 46, so the number would double every generation (92, 184 …).
What is angiography? Write the name of any one treatment used to open a blocked coronary artery.
Answer
Angiography is a test that shows the blood vessels: a dye that X-rays can’t pass through is put into the blood through a thin tube guided into the coronary arteries, and a live X-ray video is taken, so any narrowing or blockage shows up.
Treatment, any one: angioplasty and stenting (a balloon on a catheter squashes the plaque and a metal-mesh stent holds the artery open), or coronary artery bypass surgery (a healthy vessel is sewn on to carry blood round the blockage).
Marking scheme
- Angiography: a dye that X-rays can’t pass through is put into the arteries and X-rayed, to show narrowing or blockage.
- Any one treatment: angioplasty and stenting, or bypass surgery.
Every May and June, people from Dolpa, Darchula and Mugu camp in the high pastures to collect yarsagumba.
- i.Yarsagumba is not a plant. What is it, and why is it called “summer grass, winter worm”?
- ii.Why must the collection of yarsagumba be limited?
Answer
- i.It is a fungus that grows inside a caterpillar in the soil, feeds on it and kills it. In winter it is seen as the dead caterpillar (the “worm”); in spring and summer the fungus’s brown stalk grows up out of the caterpillar’s head, above the ground, like a blade of grass.
- ii.So much is collected that it is now listed as vulnerable. If the stalks are all picked before they release their spores, few new caterpillars are infected, and it could disappear (along with the income it gives mountain families).
Marking scheme
- i. A fungus growing on (feeding on) a caterpillar: the caterpillar below the ground (worm), the stalk above it (grass).
- ii. Over-collection has made it vulnerable; picked before releasing spores, it can’t spread, so it may die out.
Suman calibrated a thermometer with no scale in Kathmandu. With its bulb in melting ice, the thread stopped 3 cm above the bulb, and he marked it 0 °C. With the bulb held in the steam above boiling water, it stopped at 23 cm, and he marked it 100 °C. He divided the space between into equal parts.
- i.When he put the bulb in a cup of warm water, the thread stood at 12 cm. What temperature does his thermometer show?
- ii.His teacher said the reading is a little too high. What went wrong in his calibration?
Answer
- i.
- ii.The upper fixed point is the steam above water boiling at one atmosphere of pressure. The air pressure in Kathmandu is lower, so water there boils at only about 95 °C. His “100 °C” mark is really at about 95 °C, so every reading above 0 °C is too high (the water was really about 43 °C).
Marking scheme
- i. 45 °C.
- ii. Water boils below 100 °C (about 95 °C) in Kathmandu because of the lower air pressure, so his upper fixed point was not 100 °C.
Sita reads her book and then looks up at a mountain far away, and sees both clearly. How does her eye focus on each?
Answer
Near (the book): the ciliary muscles contract, the suspensory ligaments slacken, and the eye lens bulges thicker: its focal length becomes shorter, so it bends the spreading rays from the book strongly enough to focus them on the retina.
Far (the mountain): the ciliary muscles relax, and the lens is pulled thin: its focal length becomes longer, just right to focus the nearly parallel rays on the retina. This adjustment is called accommodation.
Marking scheme
- Near: ciliary muscles contract, the lens becomes thicker (shorter focal length).
- Far: ciliary muscles relax, the lens becomes thinner (longer focal length); in both cases the image falls on the retina.
Rojan held a convex lens in sunlight and moved a sheet of paper behind it until the image of the Sun was a tiny, sharp spot, 20 cm from the lens. He then wrote: .
- i.What mistake did he make? Calculate the correct power of the lens.
- ii.His friend’s lens has a power of +2 D. Which of the two lenses is thicker (more curved)? Give a reason.
Answer
- i.He put the focal length in centimeters; it must be in meters. f = 20 cm = 0.2 m, so .
- ii.Rojan’s lens. Its power is greater (+5 D against +2 D) and its focal length shorter (20 cm against 50 cm); a more strongly curved, thicker lens bends light more.
Marking scheme
- i. Focal length must be in meters: P = 1/0.2 = +5 D.
- ii. Rojan’s lens, because it has the greater power (shorter focal length).
Pratik filled a glass tank with water and shone a laser pointer up through its side, so that the beam met the water’s surface from below. At an angle of incidence of 30° the beam came out into the air, bent away from the normal; at 49° it skimmed along the surface.
- i.What will happen to the beam at an angle of incidence of 60°? Name this.
- ii.He then shone the laser from the air down onto the water at 60°, but the beam still went into the water. Why could total internal reflection not happen this time?
Answer
- i.No light will come out into the air: all of it is reflected back into the water, obeying the law of reflection. This is total internal reflection; 60° is greater than the critical angle of water, 49°.
- ii.Total internal reflection happens only when light goes from a denser to a rarer medium. From air into water the light goes from rarer to denser, so it bends towards the normal; its angle of refraction is always less than the angle of incidence and can never reach 90°, so some light always enters the water.
Marking scheme
- i. All the light is reflected back into the water: total internal reflection (60° is greater than the critical angle, 49°).
- ii. It needs light going from a denser to a rarer medium; from air into water the ray bends towards the normal, so it always enters.
Sima put 5 g of potassium chlorate in test tube A, and 5 g of potassium chlorate mixed with 1 g of manganese dioxide in test tube B, and heated both in the same way. Tube B gave off oxygen much faster than tube A. When it had finished, she dissolved the solid left in B in water, filtered it, and dried the black powder: it weighed 1 g.
- i.What is the role of the manganese dioxide, and which of her results shows it?
- ii.Her friend says tube B will give more oxygen in all than tube A. Is he right? Give a reason.
Answer
i. It is a (positive) catalyst: it speeds up the decomposition of potassium chlorate without being changed itself. Her results show both: B gave oxygen much faster, and the same 1 g of black manganese dioxide was got back at the end.
ii. No. The oxygen comes only from the potassium chlorate, and both tubes had the same 5 g of it. A catalyst changes only the rate of a reaction, not how much product it gives (it isn’t used up), so B gives the same amount of oxygen, only sooner.
Marking scheme
- i. MnO₂ is a catalyst (speeds up the reaction without being changed): B was faster and the 1 g of MnO₂ was got back unchanged.
- ii. No: the oxygen comes from the same 5 g of KClO₃; a catalyst changes the rate, not the amount of product.
Farmers in Jumla grow tomatoes and other vegetables in winter inside tunnels of clear plastic.
- i.Why does the air inside the tunnel stay warmer than the air outside?
- ii.Write any one other use of such artificial greenhouses.
Answer
- i.Sunlight passes through the clear plastic and warms the soil and plants, which give out long-wave infrared. The plastic stops the warm air from blowing away and mixing with the cold air outside, and it holds back some of the infrared, so the heat stays inside (the artificial greenhouse effect).
- ii.Any one: plants of any season can be grown all year round; summer crops can be grown in winter or in cold places; flowers, leafy vegetables, fruits and seedlings can be produced; plants of cold places can be kept alive; farmers can earn more by selling vegetables out of season.
Marking scheme
- i. Sunlight enters and warms the inside; the plastic keeps the warm air (and some infrared) in.
- ii. Any one correct use.
To make jaand and raksi, cooked grain is mixed with marcha and left to ferment in a closed pot, and the brew is then distilled.
- i.Why is the pot kept closed while it ferments?
- ii.Why does distilling the brew give a stronger liquid (raksi) with more alcohol?
Answer
- i.The yeast in marcha turns sugar into ethanol and carbon dioxide only without air (C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂). With air, other microbes would turn the alcohol into vinegar.
- ii.Ethanol boils at 78 °C, below water’s 100 °C, so when the brew is heated, its vapor is richer in alcohol than the brew; condensing that vapor gives a liquid with more alcohol.
Marking scheme
- i. Yeast makes alcohol only without air (with air it turns to vinegar).
- ii. Ethanol boils at a lower temperature (78 °C) than water, so the vapor, condensed, is richer in alcohol.
Kanchi’s grandmother cleans the greasy cooking pots with a paste of wood ash and water, and the dull brass lamp of the temple with lemon juice. Kanchi says, “Both of them work because they are acids.”
- i.Is Kanchi right about the wood ash? How does it remove grease?
- ii.How does lemon juice make the dull brass shine?
Answer
- i.No. Wood ash is alkaline: it contains potassium carbonate (potash), which turns grease into a kind of soap that washes away; the paste also scrubs.
- ii.Lemon juice is acidic: its citric acid dissolves the dull green-black layer of copper compounds on the brass, so the shiny metal shows.
Marking scheme
- i. No: wood ash is alkaline (potassium carbonate) and turns grease into a kind of soap.
- ii. The citric acid of lemon dissolves the dull layer (of copper compounds) on the brass.
Section D
7 × 4 = 28Write long answers to the following questions.
Rohan wanted to find out whether the height from which a toy car rolls down a ramp affects how far it goes along the floor. He did this:
- He let the car go from a height of 10 cm on the ramp and measured how far it rolled along the cement floor: 140 cm.
- The cement floor was busy, so for a height of 20 cm he moved the ramp onto the carpet in the next room: 95 cm.
- Back on the cement floor, he gave the car a little push at 30 cm to start it: 310 cm.
He concluded, “The height of the ramp makes no clear difference to the distance.”
- i.Name the independent and the dependent variable in his experiment. (1)
- ii.Write the two mistakes he made in steps 2 and 3. (1)
- iii.Is his conclusion valid? Give a reason. (1)
- iv.How should he do the experiment again so that the result is reliable? On which axis of a graph should he put the height? (1)
Answer
- i.Independent: the height from which the car is let go (what he changes). Dependent: the distance the car rolls along the floor (what he measures).
- ii.In step 2 he changed the floor (carpet instead of cement), and in step 3 he pushed the car, so it did not start from rest. The kind of floor and the starting speed should both have been controlled (kept the same).
- iii.No. Three things changed at once (the height, the floor and the push), so he can’t tell which one caused each distance: the carpet slowed the car at 20 cm, and the push sped it up at 30 cm. It was not a fair test, so it can’t show whether height matters.
- iv.Use the same car, the same ramp and the same floor every time, and let the car go from rest each time, changing only the height (say 10, 20 and 30 cm). Repeat each height three times and take the average distance. The height, the independent variable, goes on the horizontal x-axis, and the distance up the vertical y-axis.
Marking scheme
- i. Independent: the height; dependent: the distance rolled.
- ii. He changed the floor (step 2) and pushed the car (step 3): variables that should have been controlled.
- iii. Not valid: more than one variable changed, so the cause of the distances can’t be known (not a fair test).
- iv. Change only the height, keep floor and start the same, repeat and average; the height on the x-axis.
A beekeeper in Chitwan was in a hurry to sell honey. He lifted frames from his hive before the bees had sealed most of the cells with wax caps, and spun the honey out. A few weeks later, the honey in his jars had gone frothy and smelled sour, while honey he had taken from sealed cells a month earlier was still good.
- i.Describe, step by step, how bees turn nectar into honey. (2)
- ii.What went wrong with the honey from the unsealed cells? (1)
- iii.Why does ripe honey, kept sealed, not go bad for years? (1)
Answer
- i.A forager sucks up nectar, mostly water (often 60–80%) with sucrose, into her honey stomach. On the way home and in the hive, the bees add an enzyme (invertase) that splits the sucrose into the simpler sugars glucose and fructose. House bees spread the nectar thinly in the cells and fan it with their wings, so that the water evaporates. When the water has dropped below about 18%, they seal the cell with a wax cap.
- ii.The bees had not finished drying it: honey in unsealed cells still had too much water. Watery honey ferments, which made it frothy and sour.
- iii.Ripe honey has so little water and so much sugar that it pulls water out of any germ that lands in it; it is also slightly acidic, and an enzyme the bees add makes a little hydrogen peroxide, a germ killer.
Marking scheme
- i. Nectar sucked into the honey stomach; an enzyme (invertase) splits sucrose into glucose and fructose.
- i. Bees fan it to evaporate water (to below about 18%) and then seal the cell with wax.
- ii. Unsealed honey still had too much water, so it fermented.
- iii. Little water and much sugar (pulls water out of germs), or acidic, or hydrogen peroxide.
A laboratory technician in Dharan took two samples of a patient’s blood. She put sample P in a plain glass tube and left it to stand. She put sample Q in a tube with a chemical that stops blood from clotting, and spun it in a centrifuge. After an hour, P had set into a dark red lump in a pale yellow liquid, and Q had separated into three layers.
- i.Name the three layers in Q, from the top, and write the share of the blood in the top layer. (1)
- ii.Explain how the lump in P formed. (1)
- iii.The pale liquid around the lump in P is not plasma. What is it, and how is it different from plasma? (1)
- iv.The patient has dengue fever. Her platelet count is 40,000 per mm³, and her gums bleed. A relative says she has hemophilia. Is he right? Give a reason. (1)
Answer
i. From the top: plasma (a pale yellow liquid, about 55% of the blood); a thin buffy coat of white blood cells and platelets (less than 1%); and the red blood cells at the bottom (about 45%), the heaviest part.
- ii.The platelets stuck together and released chemicals that, step by step, turned the soluble plasma protein fibrinogen into long threads of fibrin. The fibrin threads made a net that trapped the red blood cells: a clot.
- iii.It is serum: plasma with its fibrinogen removed (used up in making the clot). So, unlike plasma, serum cannot clot.
- iv.No. A normal count is 1.5 to 4.5 lakh platelets per mm³; 40,000 is far too low. Bleeding from too few platelets is thrombocytopenia, which dengue causes. Hemophilia is an inherited disease in which a clotting protein is missing, while the platelets are normal.
Marking scheme
- i. Plasma (about 55%), buffy coat (white cells and platelets), red blood cells.
- ii. Platelets turn fibrinogen into fibrin threads, whose net traps red cells (a clot).
- iii. Serum: plasma without fibrinogen, so it can’t clot.
- iv. No: her platelets are too few (thrombocytopenia, from dengue); hemophilia is an inherited lack of a clotting protein with normal platelets.
Ashok did Activity 7.7. He hung a U-shaped frame, with a stone tied to a slack thread inside it, from a spring balance, as shown in the figure. Held still, the balance read 3 N. Then he let go of everything from 2.5 m above a cushion. (g = 9.8 m/s²)
- i.What did the balance read while it fell, and what happened to the thread? (1)
- ii.Calculate the speed with which the frame hit the cushion. (1)
- iii.Calculate the time it took to fall. (1)
- iv.Ashok’s friend says, “The balance read that because gravity stopped acting on the frame while it fell.” Is he right? Give a reason. (1)
Answer
- i.The balance read zero, and the stone stopped pulling on its thread: the thread went loose, and the stone stayed where it was in the frame, as if floating (weightlessness).
- ii.u = 0, h = 2.5 m. , so .
- iii.
- iv.No. Gravity kept pulling all the time; it is what made everything fall. The balance, the frame and the stone all fell together with the same acceleration g, so nothing pulled on anything else. What became zero is the apparent weight, not the force of gravity.
Marking scheme
- i. Zero; the thread went loose (the stone no longer pulled on it).
- ii. v² = u² + 2gh: v = 7 m/s.
- iii. t = v/g = 0.71 s.
- iv. No: gravity still acts (it makes them fall); all fall with the same acceleration, so the apparent weight is zero.
Rekha connected the two ends of a coil to a galvanometer, with no cell in the circuit, and moved a bar magnet in and out of it (Activity 11.5).
- i.What does the needle of the galvanometer do when she pushes the north pole into the coil, holds it still inside, and then pulls it out? (1)
- ii.Why is a current produced only while the magnet moves? (1)
- iii.State Faraday’s law of electromagnetic induction. (1)
- iv.Raju did the same with a coil of only five turns and a weak magnet, moving it slowly, and the needle hardly moved. Write any two changes that would make the needle move further. (1)
Answer
- i.Pushed in: the needle moves to one side. Held still: it comes back to zero. Pulled out: it moves to the other side.
- ii.An e.m.f. is induced only while the magnetic flux linked with the coil changes. A moving magnet changes the number of field lines through the coil; a still one gives a steady flux, so no e.m.f. is induced and no current flows (electromagnetic induction).
- iii.When there is relative motion between a conductor and a magnet, an e.m.f. is induced in the conductor, and its size is directly proportional to the rate of change of the magnetic flux linked with it.
- iv.Any two: use a coil with more turns; use a stronger magnet; move the magnet faster.
Marking scheme
- i. Moves one way going in, back to zero when still, the other way coming out.
- ii. Current is induced only while the magnetic flux through the coil changes (a still magnet gives a steady flux).
- iii. The induced e.m.f. is directly proportional to the rate of change of magnetic flux.
- iv. Any two: more turns, a stronger magnet, faster motion.
Ramila connected a cell, a milliammeter and two crocodile clips in a circuit. She clipped three elements between the clips in turn and read the current.
| Element | Magnesium (ribbon) | Sulphur (lump) | Silicon (wafer) |
|---|---|---|---|
| Current (mA) | 180 | 0 | 4 |
- i.From her results, which element is a metal, which a non-metal, and which a metalloid? (1)
- ii.Write the electronic configuration of silicon (atomic number 14) in subshells, and its group and period in the modern periodic table. (1)
- iii.Why is silicon used in the chips of phones and computers? (1)
- iv.What is the valency of silicon? Write the molecular formula of the compound it forms with chlorine. (1)
Answer
- i.Magnesium conducts well: a metal. Sulphur doesn’t conduct: a non-metal. Silicon conducts, but much less than a metal and more than a non-metal: a metalloid.
- ii.1s², 2s² 2p⁶, 3s² 3p² (shells 2, 8, 4). Four electrons in the third shell: group IVA (14), period 3.
- iii.Because it is a semiconductor: as a metalloid it conducts electricity less than metals and more than non-metals, which is what the tiny switches (transistors) in chips need.
- iv.With four valence electrons it shares four: valency 4. Chlorine has valency 1, so the formula is SiCl₄.
Marking scheme
- i. Magnesium metal, sulphur non-metal, silicon metalloid.
- ii. 1s², 2s² 2p⁶, 3s² 3p²; group IVA (14), period 3.
- iii. It is a semiconductor (conducts less than metals, more than non-metals).
- iv. Valency 4; SiCl₄.
Draw a neat, labeled diagram of the electro-refining of copper. Write the reactions at the anode and at the cathode, and one reason why copper for electric wires is refined in this way.
Answer
A block of impure copper is the anode, joined to the positive terminal of the battery; a thin sheet of pure copper is the cathode, joined to the negative terminal. Both hang in copper sulphate solution (the electrolyte) in a voltameter. Copper leaves the anode as ions and is deposited on the cathode; the impurities stay in the solution or fall below the anode as anode mud.
Reason: electro-refined copper is very pure (about 99.99%), and electric wires need such pure copper, because even tiny impurities make copper conduct much worse.
Marking scheme
- Apparatus correct: impure copper anode to +, pure copper cathode to −, both in copper sulphate solution.
- At least five parts labeled (battery, anode, impure copper, cathode, pure copper, copper sulphate solution, anode mud, voltameter).
- Anode: Cu → Cu²⁺ + 2e⁻; cathode: Cu²⁺ + 2e⁻ → Cu.
- Very pure copper (about 99.99%) is needed for wires, as impurities make it conduct much worse.
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