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SEE Model Paper 3

Full marks: 75Time: 3 hours

All questions are compulsory.

Write your answers on paper first. Then open each answer and its marking scheme, and give yourself one mark for each point you got. In multiple choice, your first choice counts.

Section A

10 × 1 = 10

1. Choose the correct option for each of the following questions.

a.

What number is the binary number 10110 in the decimal system?

Pick an answer to see why.

b.

Which of the following plants has no vascular tissue (no xylem and phloem)?

Pick an answer to see why.

c.

A mule, the offspring of a donkey and a horse, is strong and useful, but it can't have young of its own. Why?

Pick an answer to see why.

d.

Red cells of which blood group can be given safely to a patient of any blood group?

Pick an answer to see why.

e.

The mass of each of two bodies is doubled, and the distance between them is made three times as large. What happens to the gravitational force F between them?

Pick an answer to see why.

f.

A hydrometer floats in water. When it is put in kerosene, it sinks deeper. Why?

Pick an answer to see why.

g.

Which kind of thermometer measures the temperature of an object without touching it?

Pick an answer to see why.

h.

The a.c. supply in Nepal has a frequency of 50 Hz. What does this mean?

Pick an answer to see why.

i.

A statement and two arguments are given below.

Statement: The rusting of iron is a chemical change.

Argument 1: A new substance, rust, is formed, with properties different from those of iron.

Argument 2: Rust turns back into iron when it is heated gently.

Pick an answer to see why.

j.

A hydrocarbon has 3 carbon atoms and 4 hydrogen atoms in its molecule. Which of the following is it?

Pick an answer to see why.

Section B

9 × 1 = 9

2. Write very short answers to the following questions.

a.

Newton's law of gravitation gives G=Fd2m1m2 G = \dfrac{Fd^2}{m_1m_2} . Write the unit of G in fundamental units.

Answer

unit of G=N×m2kg×kg=kg m s−2×m2kg2=m3 kg−1 s−2 \text{unit of } G = \frac{\text{N} \times \text{m}^2}{\text{kg} \times \text{kg}} = \frac{\text{kg m s}^{-2} \times \text{m}^2}{\text{kg}^2} = \text{m}^3\,\text{kg}^{-1}\,\text{s}^{-2}
(In derived units, N m²/kg².)

Marking scheme
  • m³ kg⁻¹ s⁻² (from N m²/kg², with N = kg m s⁻²).
b.

Bryophytes are called the amphibians of the plant kingdom. Why?

Answer

Because they live on land but need water to reproduce: their male gametes swim to the egg through a film of water.

Marking scheme
  • They live on land but need water for fertilization (the male gametes swim to the egg).
c.

Which blood cells help to stop bleeding from a cut?

Answer

Platelets (thrombocytes). They stick to the torn edge and to each other to make a plug, and help a clot to form.

Marking scheme
  • Platelets (thrombocytes).
d.

State Pascal’s law.

Answer

When pressure is applied at any point of a liquid in a closed container, it is transmitted equally in all directions, throughout the liquid, and acts at right angles to the walls of the container.

Marking scheme
  • Pressure applied to a liquid in a closed container is transmitted equally in all directions (acting at right angles to the walls).
e.

2 kg of water at 70 °C is mixed with 3 kg of water at 20 °C. Find the final temperature of the mixture, if no heat is lost to the surroundings.

Answer

Heat lost by the hot water = heat gained by the cold water. Let the final temperature be T.
2×4200×(70−T)=3×4200×(T−20)⇒140−2T=3T−60⇒T=40 °C 2 \times 4200 \times (70 - T) = 3 \times 4200 \times (T - 20) \quad\Rightarrow\quad 140 - 2T = 3T - 60 \quad\Rightarrow\quad T = 40\ °\text{C}

Marking scheme
  • Heat lost = heat gained, giving T = 40 °C.
f.

The core of a transformer is made of thin iron sheets with an insulating layer between them, not of a solid block of iron. Why?

Answer

The changing magnetic field would induce swirling currents (eddy currents) in a solid core, which would heat it and waste energy. The insulating layers break up these currents, so less energy is lost.

Marking scheme
  • To stop eddy currents in the core, which would waste energy as heat.
g.

Lithium and fluorine both have two shells, but a fluorine atom is smaller than a lithium atom. Why?

Answer

Fluorine’s nucleus has 9 protons and lithium’s only 3. The bigger positive charge pulls the same two shells in more tightly, so the fluorine atom is smaller.

Marking scheme
  • Fluorine has more protons (9 against 3), so its nucleus pulls the shells in more tightly.
h.

On a hot afternoon, a shopkeeper opened a bottle of strong ammonia solution (liquor ammonia), and the liquid spurted out towards his face. Why did this happen?

Answer

Gases dissolve less in warm water. On the hot day, ammonia gas came out of the solution and built up pressure under the lid, which pushed the gas and the liquid out as soon as he opened it. The bottle should first be cooled in cold water or ice, so that the gas dissolves back in.

Marking scheme
  • Ammonia dissolves less when warm, so the escaping gas built up pressure under the lid (the bottle should be cooled first).
i.

Why are alkanes called saturated hydrocarbons?

Answer

Because their carbon atoms are joined only by single covalent bonds, so each carbon already holds as many hydrogen atoms as it can and can take no more.

Marking scheme
  • They have only single bonds between carbon atoms, so they can hold no more hydrogen.

Section C

14 × 2 = 28

Write short answers to the following questions.

3.
[2]

While revising, Bina wrote the first equation of motion as v = u + at², and Kiran wrote the third as v² = u² + as.

  • i.Check each equation by its units.
  • ii.Kiran says, “My equation has the same units on both sides, so it must be correct.” Is he right? Give a reason.
Answer

i. Bina: the left side, v, is in m s⁻¹, and so is u; but at² is m s⁻² × s² = m. A speed can’t be added to a distance, so her equation is wrong.
Kiran: v² and u² are in m² s⁻², and as is m s⁻² × m = m² s⁻². Every term has the same units, so his equation could be right.
ii. No. Numbers have no units, so a check by units can’t find a missing number. The correct equation is v² = u² + 2as: Kiran has left out the 2, and the units still match. Units can show that an equation is wrong, but not that it is right.

Marking scheme
  • i. Bina’s equation is wrong (at² is in m, v in m s⁻¹); Kiran’s has the same units (m² s⁻²) in every term.
  • ii. No: numbers have no units, so a missing 2 (v² = u² + 2as) can’t be found by units.
4.
[2]

Anu sends a photo from her phone in Kathmandu to her sister in Japan.

  • i.How does the internet carry the photo to her sister?
  • ii.On the way, a cable is cut by a landslide, but the photo still arrives complete. How is this possible?
Answer
  • i.The photo is cut into small packets of bits, and each packet carries the destination address and a number. Routers pass each packet on towards the address, and her sister's phone puts the packets back together in order by their numbers.
  • ii.Each router chooses a good next step at that moment, so when one cable is broken, the packets simply take other routes round the break. They may arrive out of order, but the phone puts them back in order by their numbers and asks again for any that went missing.
Marking scheme
  • i. The photo is cut into numbered, addressed packets, which routers pass along and the phone puts back in order.
  • ii. Routers send the packets by other routes round the break (and missing packets are asked for again).
5.
[2]

Read the given passage and answer the questions that follow.

Suresh got an SMS: “Your digital wallet has been blocked. Click this link to open it again.” He clicked the link and typed his wallet password on the page that opened. A few minutes later, a man phoned him, said he was calling from the wallet company, and asked for the OTP that had just come to Suresh’s phone. Suresh read it out. That evening, Rs 15,000 had gone from his wallet.

  • i.Write any two mistakes Suresh made.
  • ii.Suggest any two things that would have kept his money safe.
Answer
  • i.Any two: he clicked a link in an unknown message; he typed his password on a page he reached from that link; he gave the OTP to a caller (no real wallet company ever asks for an OTP or PIN); he believed the caller without checking.
  • ii.Any two: never click links in messages that say an account is blocked or a prize is won, and open the real app yourself instead; never share an OTP or PIN with anyone; turn on two-step verification and use a strong, different password for each account; call the company’s own number to check; report the message and change the password at once.
Marking scheme
  • i. Two mistakes (clicked the link, typed his password on that page, told the OTP to the caller).
  • ii. Two safe practices (don’t click such links, never share an OTP or PIN, two-step verification or strong passwords, check with the company itself).
6.
[2]

Write any two characteristics of the class Mammalia.

Answer

Any two:

  • a.The body is covered with hair (or fur).
  • b.They have mammary glands, which make milk to feed the young.
  • c.They are viviparous (give birth to young) and fertilization is internal.
  • d.They are homeothermic (warm-blooded), breathe with lungs and have a four-chambered heart.
  • e.They have external ears (pinnae) and teeth of different kinds.
Marking scheme
  • One correct characteristic.
  • A second correct characteristic.
7.
[2]

Write any two differences between DNA and RNA.

Answer

Any two:

DNA RNA
has two strands (a double helix) usually has one strand
its sugar is deoxyribose its sugar is ribose
has the base thymine (T) has the base uracil (U) in place of thymine
found mainly in the chromosomes in the nucleus found mostly in the cytoplasm and ribosomes
stores and passes on hereditary information helps to make proteins
Marking scheme
  • One correct difference.
  • A second correct difference.
8.
[2]

Pooja sat quietly for five minutes and then counted 19 pulse beats at her wrist in 15 seconds. After skipping for one minute, she counted 31 beats in 15 seconds.

  • i.Calculate her heart rate at rest.
  • ii.Calculate her heart rate after skipping. Does it mean that she has tachycardia? Give a reason.
Answer
  • i.19 × 4 = 76 beats a minute, within the normal range of 60 to 100.
  • ii.31 × 4 = 124 beats a minute. No, she doesn’t have tachycardia: tachycardia is a heart rate above 100 a minute at rest. The heart rate rises with exercise in everyone and falls back when they rest.
Marking scheme
  • i. 76 beats per minute.
  • ii. 124 beats per minute; not tachycardia, because tachycardia means a fast rate at rest (the rate rises normally with exercise).
9.
[2]

Two loaded trucks, each of mass 10,000 kg, are parked with their centers 5 m apart. (G = 6.67 × 10⁻¹¹ N m²/kg²)

  • i.Calculate the gravitational force between them.
  • ii.Why don’t the trucks move towards each other?
Answer
  • i.F=Gm1m2d2=6.67×10−11×10,000×10,00052=6.67×10−325=2.67×10−4 N F = \frac{Gm_1m_2}{d^2} = \frac{6.67 \times 10^{-11} \times 10{,}000 \times 10{,}000}{5^2} = \frac{6.67 \times 10^{-3}}{25} = 2.67 \times 10^{-4}\ \text{N}
  • ii.The force is very small, about a quarter of a thousandth of a newton, while each truck weighs about 98,000 N. The friction between the tyres and the road is far larger than this pull, so the trucks don’t move.
Marking scheme
  • i. F = Gm₁m₂/d² = 2.67 × 10⁻⁴ N.
  • ii. The force is far too small to overcome the friction between the tyres and the road.
10.
[2]

At the height of the Space Station, the acceleration due to gravity is still about 8.69 m/s², yet the astronauts float inside it. Why?

Answer

Gravity still pulls the astronauts and the station: it is what keeps the station in orbit. But the station is falling freely round the Earth all the time, and the astronauts fall with it at the same acceleration. So they don’t press on the floor or pull on anything: their apparent weight is zero, and they float. This is weightlessness.

Marking scheme
  • Gravity still acts on them (it keeps the station in orbit).
  • The station and the astronauts fall freely together, so they press on nothing (apparent weight zero).
11.
[2]

The tank of a solar water heater on a roof holds 100 kg of water. On a sunny day the water warms from 15 °C to 55 °C. (Specific heat capacity of water = 4,200 J/kg °C)

  • i.How much heat does the water take in?
  • ii.If the tank held 100 kg of a liquid whose specific heat capacity is half that of water, how much would the same heat raise its temperature?
Answer
  • i.Q=ms(T2−T1)=100×4200×(55−15)=16,800,000 J Q = ms(T_2 - T_1) = 100 \times 4200 \times (55 - 15) = 16{,}800{,}000\ \text{J} (16.8 MJ)
  • ii.ΔT=Qms=16,800,000100×2100=80 °C \Delta T = \frac{Q}{ms} = \frac{16{,}800{,}000}{100 \times 2100} = 80\ °\text{C}

Twice the rise in water's temperature: the same heat warms a liquid with half the specific heat capacity twice as much. (That is why water, with its high specific heat capacity, is used: it stores a lot of heat with a small rise in temperature.)

Marking scheme
  • i. Q = ms(T₂ − T₁) = 16,800,000 J (16.8 MJ).
  • ii. ΔT = Q/(ms) = 80 °C.
12.
[2]

A doctor in Pokhara passes an endoscope through a patient's mouth, down the esophagus and into the stomach to look for an ulcer. The tube bends round several curves on the way.

  • i.How does the light reach the stomach, though the tube is bent?
  • ii.Bishal says, “If the cladding of each fiber were made of the same glass as its core, the light would pass more easily and the endoscope would work better.” Is he right? Give a reason.
Answer
  • i.The light travels in the endoscope's optical fibers. It meets the edge of each fiber's core at more than the critical angle, so it is totally internally reflected again and again and stays in the core, whether the fiber is straight or bent.
  • ii.No. Total internal reflection happens only when light goes from a denser into a rarer medium. The cladding has a lower refractive index than the core, which makes the core the denser medium. With cladding of the same glass, nothing would totally reflect the light at the core's edge: it would leak out through the sides, and little would reach the far end.
Marking scheme
  • i. The light meets the core's edge at more than the critical angle and is totally internally reflected again and again.
  • ii. No: the lower refractive index of the cladding makes the core denser, which total internal reflection needs; with the same glass the light would leak out.
13.
[2]

Electricity from a power station is sent across the country at 132 kV, but homes get it at 230 V.

  • i.Why is it sent at a high voltage?
  • ii.How is the voltage brought down to 230 V before it reaches homes?
Answer
  • i.For the same power, a higher voltage needs a smaller current (power = voltage × current). The heat wasted in the wires grows with the square of the current, so a small current wastes much less energy on the long journey.
  • ii.By step-down transformers: at substations and on poles near the houses, they lower the voltage in stages to 230 V.
Marking scheme
  • i. High voltage means a small current, so less energy is lost as heat in the wires.
  • ii. By step-down transformers (at substations and near homes).
14.
[2]

Element X has atomic number 15.

  • i.Write its electronic configuration by subshells, and its group and period in the modern periodic table.
  • ii.Which has the higher electronegativity, X or the element with atomic number 7? Give a reason.
Answer
  • i.1s², 2s² 2p⁶, 3s² 3p³. Its third (outermost) shell holds 5 electrons, so it is in group VA (15) and period 3. (X is phosphorus.)
  • ii.The element with atomic number 7 (nitrogen, 1s², 2s² 2p³). It is in the same group as X but one period higher, so its atom is smaller, and its nucleus pulls an extra electron more strongly.
Marking scheme
  • i. 1s², 2s² 2p⁶, 3s² 3p³; group VA (15), period 3.
  • ii. Atomic number 7 (nitrogen): a smaller atom in the same group, so it attracts electrons more strongly.
15.
[2]

Sarita left copper sulphate solution in an iron bucket overnight. In the morning the inside of the bucket was covered with a reddish-brown layer, and the blue solution had turned pale green.

  • i.Write the balanced chemical equation of the reaction.
  • ii.Would the same thing happen in a silver bowl? Give a reason.
Answer

i. Fe+CuSO4→FeSO4+Cu \text{Fe} + \text{CuSO}_4 \rightarrow \text{FeSO}_4 + \text{Cu}
The reddish-brown layer is copper, and the pale green solution is iron(II) sulphate. It is a single displacement reaction.
ii. No. Silver is below copper in the reactivity series (K > Na > Ca > Mg > Al > Zn > Fe > Pb > (H) > Cu > Hg > Ag > Au), so it is less reactive and can’t displace copper from copper sulphate. Iron is above copper, so it can.

Marking scheme
  • i. Fe + CuSO₄ → FeSO₄ + Cu.
  • ii. No: silver is less reactive than copper, so it can’t displace it.
16.
[2]

Students collected rainwater at two places: near a group of brick kilns that burn coal, where its pH was 4.4, and in a hill village far from roads and factories, where its pH was 5.6.

  • i.Which sample is acid rain? Why is the other one not called acid rain, though its pH is below 7?
  • ii.Name the gas from the kilns that most likely made the first sample acidic, and write the equations by which it turns into an acid in the air.
Answer
  • i.The sample from near the kilns (pH 4.4) is acid rain. Even clean rain dissolves a little carbon dioxide from the air and is slightly acidic, with a pH of about 5.6; only rain with a pH below 5.6 is called acid rain.
  • ii.Sulphur dioxide (SO₂), from burning coal:

2SO2+O2→2SO3SO3+H2O→H2SO4 2\text{SO}_2 + \text{O}_2 \rightarrow 2\text{SO}_3 \qquad \text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4
(Oxides of nitrogen from the hot kilns add nitric acid as well.)

Marking scheme
  • i. The kiln sample (pH 4.4); clean rain is about 5.6 because of dissolved CO₂, and only rain below 5.6 is acid rain.
  • ii. Sulphur dioxide: 2SO₂ + O₂ → 2SO₃, SO₃ + H₂O → H₂SO₄.

Section D

7 × 4 = 28

Write long answers to the following questions.

17.
[4]

A beekeeper in Ilam keeps Asian hive bees (Apis cerana) beside a field of mustard. On a sunny morning, a forager comes back and dances on the vertical comb: her waggle run points 90° to the left of straight up, and each run lasts about 2 seconds.

  • i.In which direction, and roughly how far, should her sisters fly to find the food? (1)
  • ii.How do the bees turn the nectar they collect into honey? (1)
  • iii.Sealed honey can be kept for years without going bad. Why? (1)
  • iv.The farmers next to the beekeeper find that their mustard gives more seed than before the hives came. Why? (1)
Answer
  • i.Straight up on the comb stands for the direction of the sun, so they should fly 90° to the left of the sun. The longer the waggle run, the farther the food, roughly one second of waggling for each kilometer, so the food is about 2 km away.
  • ii.A forager sucks nectar (mostly water, with sucrose) into her honey stomach, and the bees add an enzyme (invertase) that splits the sucrose into glucose and fructose. House bees spread it in the cells and fan it with their wings to evaporate the water; when the water is down to under about 18%, they seal the cell with wax.
  • iii.Honey has so little water and so much sugar that it pulls water out of any germ that lands in it. It is also slightly acidic, and an enzyme the bees add slowly makes a little hydrogen peroxide, which kills germs.
  • iv.As the bees suck nectar, they carry pollen from flower to flower and pollinate the mustard, in the neighbors' fields too (they forage a kilometer or more from the hive), so more pods and seeds form.
Marking scheme
  • i. 90° to the left of the sun, about 2 km away (about one second of waggling per kilometer).
  • ii. An enzyme (invertase) splits the sucrose into glucose and fructose, and the bees fan off the water before sealing the cell.
  • iii. Too little water and too much sugar for germs to live (it draws water out of them; it is acidic and makes hydrogen peroxide).
  • iv. The bees pollinate the mustard flowers in the nearby fields, so more seeds form.
18.
[4]

In pea plants, green pod (G) is dominant over yellow pod (g). A pure green-podded plant is crossed with a yellow-podded plant, and the F₁ plants are then self-pollinated.

  • i.Write the genotype and the phenotype of the F₁ plants. (1)
  • ii.Show the F₂ generation in a checkerboard (Punnett square). (1)
  • iii.Of 600 F₂ plants, about how many will have yellow pods? And about how many of the green-podded F₂ plants will be pure (GG)? (1)
  • iv.No F₁ plant had yellow pods, but yellow pods came back in F₂. Which of Mendel's laws explains this? Explain briefly. (1)
Answer
  • i.GG × gg: the parents give only G and only g gametes, so every F₁ plant is Gg, with green pods.
  • ii.F₁ × F₁ is Gg × Gg; each parent gives G and g gametes.
G g
G GG (green) Gg (green)
g Gg (green) gg (yellow)
  • iii.The ratio is 3 green : 1 yellow, so about 14×600= \tfrac{1}{4} \times 600 = 150 plants with yellow pods. The other 450 are green, and 1 in 3 of them is pure (GG : Gg = 1 : 2): about 150 pure GG plants.
  • iv.The law of purity of gametes (segregation). The alleles G and g sit together in the F₁ hybrid without mixing; when it makes gametes they separate, and each gamete gets only one of them. Two g gametes can meet at fertilization, giving gg plants with yellow pods.
Marking scheme
  • i. Gg; green pods.
  • ii. A correct checkerboard: GG, Gg, Gg, gg.
  • iii. About 150 with yellow pods; about 150 pure green (GG).
  • iv. The law of purity of gametes (segregation): the alleles separate into different gametes, so g can meet g in F₂.
19.
[4]

Read the given passage and answer the questions that follow.

A few years ago, traders came to a hill village and paid well for the bark and leaves of the lauth salla (Himalayan yew) trees in its community forest. Some villagers stripped the bark from all the way round the trunks, and within two years many of the trees had died. An old woman says that panch aunle used to grow in the pastures above the village too, but so many of its roots were dug up that hardly any are left.

  • i.What medicine is made from lauth salla, and how should the bark have been collected so that the trees would survive? (1)
  • ii.How could tissue culture help to bring the panch aunle back to the pastures? (1)
  • iii.Name the law Nepal has made to control the trade in endangered plants and animals, and write one thing it controls. (1)
  • iv.The villagers want the forest to earn them money for many years. Suggest two things they could do, and explain why the rare plants are “worth more alive”. (1)
Answer
  • i.Taxol, a medicine for cancer. They should have taken only as much as the trees could grow back: some bark from each tree, never stripped from the whole trunk.
  • ii.A tiny piece of a panch aunle plant is grown on a jelly of nutrients in a clean glass jar, where it multiplies into hundreds of identical small plants. These can be raised and planted out in the pastures without digging up any more plants from the wild.
  • iii.The Endangered Wild Fauna and Flora International Trade Control Act, 2073 (Nepal's law for the world agreement CITES). It sets rules on selling and trading rare wild plants and animals (and on breeding, growing and research).
  • iv.Any two: collect only as much as can grow back (for a herb, leave some plants to make seed); raise saplings of the rare plants in a nursery and plant them out; protect the places where they grow (control grazing, forest fires and cutting); stop theft and smuggling; hold awareness programs in the community. Plants left growing give a harvest year after year, but a plant dug up and sold all at once is gone for good.
Marking scheme
  • i. Taxol (a cancer medicine); take only what can grow back, never stripping the bark from the whole trunk.
  • ii. Tissue culture grows hundreds of identical plantlets from a tiny piece, to plant out without taking more from the wild.
  • iii. The Endangered Wild Fauna and Flora International Trade Control Act, 2073, which controls their trade (or breeding, growing, research).
  • iv. Two sensible measures (harvest only what grows back, nurseries, protect the habitat, stop smuggling, awareness), with the reason that living plants give an income year after year.
20.
[4]

An old watch repairer in Bhaktapur looks at the tiny parts of a watch through a convex lens of focal length 5 cm, holding each part 3 cm from the lens.

  • i.Draw a ray diagram to show how the image of a watch part is formed. (2)
  • ii.Write any two characteristics of the image. (1)
  • iii.Calculate the power of the lens. (1)
Answer

i. The part (the object) is between the principal focus F₁ and the optical center O. A ray from the top of the object parallel to the principal axis passes, after the lens, through F₂; a ray through O goes straight on. The two rays spread apart on the other side and never meet. Traced backwards (dashed), they seem to meet on the same side as the object, farther from the lens than it, where the image forms.

2F₁F₁F₂2F₂Oprincipal axisobjectvirtual image
Figure 1 An object between F₁ and O of a convex lens: the image is virtual, upright and magnified, on the same side as the object.
  • ii.Any two: it is virtual (it can’t be caught on a screen), upright (erect), magnified, and on the same side of the lens as the object.
  • iii.f=5 cm=0.05 m f = 5\ \text{cm} = 0.05\ \text{m} , so

P=1f=10.05 m=+20 D P = \frac{1}{f} = \frac{1}{0.05\ \text{m}} = +20\ \text{D}

Marking scheme
  • i. Two correct rays from the top of the object (parallel then through F₂; straight through O).
  • i. The rays traced back (dashed) to an upright, larger image on the same side as the object.
  • ii. Two characteristics: virtual, upright, magnified (on the same side as the object).
  • iii. P = 1/0.05 m = +20 D.
21.
[4]

Read the given passage and answer the questions that follow.

In 1929, the American astronomer Edwin Hubble compared how far away many galaxies are with how fast they are moving. He found that almost every galaxy is moving away from us, and that a galaxy twice as far away is moving away twice as fast. In 1964, two radio astronomers in the USA found a faint hiss of microwaves coming equally from every direction of the sky, day and night.

  • i.Write Hubble’s law in words and as a formula. (1)
  • ii.How does Hubble’s finding support the Big Bang theory? (1)
  • iii.What was the faint hiss of microwaves? (1)
  • iv.All the distant galaxies are moving away from us, in every direction. Does this mean that our galaxy is at the center of the universe? Give a reason. (1)
Answer
  • i.Galaxies are moving away from us, and the farther away a galaxy is, the faster it is moving away: v=Hd v = Hd , where v is the galaxy’s speed of recession, d its distance and H Hubble’s constant.
  • ii.If the galaxies are moving apart now, they were closer together in the past; going back far enough, everything was together in one extremely hot, dense state. That is what the Big Bang theory says: the universe began from such a state about 13.8 billion years ago and has been expanding ever since.
  • iii.The cosmic microwave background: the afterglow of the Big Bang, light released about 380,000 years after the beginning and stretched by the expansion into weak microwaves.
  • iv.No. It is space itself that is expanding, everywhere at once, so from any galaxy all the others seem to move away, like dots on a balloon being blown up. No dot, and no galaxy, is the center.
Marking scheme
  • i. The farther a galaxy, the faster it moves away; v = Hd.
  • ii. Galaxies moving apart now were together in the past, in a hot, dense state, as the Big Bang theory says.
  • iii. The cosmic microwave background, the afterglow of the Big Bang.
  • iv. No: space expands everywhere, so from any galaxy the others move away (like dots on a balloon).
22.
[4]

Zinc can be extracted from calamine, an ore of zinc carbonate.

  • i.Write the main steps of metallurgy in their correct order. (1)
  • ii.Name the step that changes calamine into zinc oxide, and write its balanced equation. (1)
  • iii.Write the balanced equation for the reduction of zinc oxide. (1)
  • iv.Name the method by which zinc is refined, and write why it suits zinc. (1)
Answer
  • i.Grinding (crushing) → concentration (removing the gangue) → oxidation (roasting or calcination) → reduction → refining.
  • ii.Calcination: heating the ore strongly without air (calamine is a carbonate ore).

ZnCO3→ΔZnO+CO2 \text{ZnCO}_3 \xrightarrow{\Delta} \text{ZnO} + \text{CO}_2
iii. Zinc oxide is heated with carbon (coke):
ZnO+C→ΔZn+CO \text{ZnO} + \text{C} \xrightarrow{\Delta} \text{Zn} + \text{CO}
iv. Distillation. Zinc has a low boiling point (907 °C): the impure zinc is heated until it boils, and the vapor is cooled back into pure zinc, leaving the impurities behind.

Marking scheme
  • i. Grinding → concentration → oxidation (roasting or calcination) → reduction → refining.
  • ii. Calcination: ZnCO₃ → ZnO + CO₂.
  • iii. ZnO + C → Zn + CO.
  • iv. Distillation, because zinc has a low boiling point.
23.
[4]

Read the given passage and answer the questions that follow.

The eco club of a school in Lalitpur made soap for the school fair. With their teacher, they heated mustard oil with sodium hydroxide solution, stirring until it became a thick paste, then stirred in some common salt and filtered the mixture. They sold the bars beside a sign: “Our soap is kind to the Bagmati.” At the next stall, washing powder was on sale. In the fair's kitchen, the club scrubbed the greasy cooking pots with wood ash, and cleaned the temple's dull brass lamps with lemon juice.

  • i.Name the process by which the soap was made, and write why common salt was added. (1)
  • ii.How does a bar of their soap lift an oily stain off a cloth? (1)
  • iii.Is their sign right? Compare their soap with the washing powder when the wastewater reaches a river. (1)
  • iv.Why does wood ash clean greasy pots, and why does lemon juice make dull brass shine? (1)
Answer
  • i.Saponification: fat or oil + sodium hydroxide → soap + glycerol. Soap dissolves less in salty water, so the salt makes the soap separate and float to the top as a solid, leaving the glycerol in the water (salting out).
  • ii.A soap molecule has a long hydrocarbon tail that dissolves in oil (hydrophobic) and an ionic head that loves water (hydrophilic). The tails dig into the grease and the heads stay in the water, so the soap wraps tiny droplets of grease into balls called micelles, which are rinsed away.
  • iii.Mostly right. Soap is biodegradable: microbes break it down, so it doesn't pollute for long. Washing powder contains phosphates, which are a fertilizer for water plants: wastewater full of them makes rivers choke with algae, which use up the oxygen fish need. (Still, no soapy water should run straight into a river; it should go to a soak pit or a treatment plant.)
  • iv.Wood ash is alkaline: it contains potassium carbonate (potash), which turns grease into a kind of soap, and its grains scrub. Lemon juice contains citric acid, which dissolves the dull green-black layer of copper compounds on the brass.
Marking scheme
  • i. Saponification; the salt makes the soap separate out (salting out).
  • ii. The oil-loving tails go into the grease and the water-loving heads stay in the water, wrapping the grease into micelles that are rinsed away.
  • iii. Soap is biodegradable, but the phosphates in washing powder feed algae that use up the oxygen in rivers.
  • iv. Ash is alkaline (its potash turns grease into soap, and it scrubs); the citric acid in lemon dissolves the copper compounds on brass.

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