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SEE Model Paper 10

Full marks: 75Time: 3 hours

All questions are compulsory.

Write your answers on paper first. Then open each answer and its marking scheme, and give yourself one mark for each point you got. In multiple choice, your first choice counts.

Section A

10 × 1 = 10

1. Choose the correct option for each of the following questions.

a.

Long ago, anyone who joined a wire to an analog telephone line could listen to the call. Why is it much harder to listen in on a digital call?

Pick an answer to see why.

b.

On a damp, shady wall beside a stream in Ilam, Pasang finds a plant with a true root, stem and feather-like leaves. Under the leaves are rows of small brown spots, and its stem has xylem and phloem, but it never bears flowers or seeds. To which group does it belong?

Pick an answer to see why.

c.

When mRNA is made, each base of one DNA strand pairs with a base of RNA: A with U (RNA has uracil in place of thymine), T with A, G with C and C with G. Which mRNA is made from the DNA strand TACGGA?

Pick an answer to see why.

d.

A ball dropped from rest hits the ground at 14 m/s. From what height was it dropped? (g = 9.8 m/s², ignore air resistance)

Pick an answer to see why.

e.

The temperature of a liquid is 323 K. What is it on the Fahrenheit scale?

Pick an answer to see why.

f.

A short-sighted person can have laser surgery instead of wearing glasses. What does the laser do?

Pick an answer to see why.

g.

According to the Big Bang theory, about how long ago did the universe begin?

Pick an answer to see why.

h.

A statement and two arguments are given below.

Statement: Mendeleev left some gaps in his periodic table.

Argument 1: He arranged the elements by their atomic numbers, and some atomic numbers were missing.

Argument 2: He left them for elements not yet discovered, and predicted their properties.

Pick an answer to see why.

i.

Which of the following is the chief ore of silver?

Pick an answer to see why.

j.

A liquid with the formula C₂H₄(OH)₂ is added to the water in car radiators in cold countries. What kind of compound is it, and why is it added?

Pick an answer to see why.

Section B

9 × 1 = 9

2. Write very short answers to the following questions.

a.

What does trimming a video clip mean?

Answer

Cutting off the unwanted parts at the start and the end of a clip, so that only the part you want to keep is left.

Marking scheme
  • Cutting off the unwanted start and end of a clip, keeping only the part wanted.
b.

To which kingdom do Amoeba and Paramecium belong?

Answer

Protista: they are eukaryotic, made of one cell with a nucleus.

Marking scheme
  • Protista.
c.

Golden rice is a rice given genes to make beta-carotene. How is it useful to people?

Answer

The body turns beta-carotene into vitamin A, so golden rice helps to prevent the blindness caused by a lack of vitamin A in people who live mostly on rice.

Marking scheme
  • Beta-carotene becomes vitamin A in the body, which prevents blindness from lack of vitamin A.
d.

The pulmonary artery carries deoxygenated blood. Why is it still called an artery?

Answer

A blood vessel is called an artery because it carries blood away from the heart, whatever the blood is like. The pulmonary artery carries blood from the right ventricle to the lungs.

Marking scheme
  • Arteries carry blood away from the heart; the pulmonary artery takes blood from the heart (right ventricle) to the lungs.
e.

Bikash is short-sighted. His far point is 80 cm from his eye. Calculate the power of the lens he needs.

Answer

He needs a concave lens that makes distant objects seem to be at his far point, so its focal length is f = −80 cm = −0.8 m.
P=1f=1−0.8 m=−1.25 D P = \frac{1}{f} = \frac{1}{-0.8\ \text{m}} = -1.25\ \text{D}

Marking scheme
  • f = −0.8 m, so P = −1.25 D (a concave lens).
f.

A flat card is held in a uniform magnetic field. In which position is the magnetic flux through the card zero?

Answer

When the face of the card lies along the field lines (the card is parallel to the lines), no lines pass through it, so the flux through it is zero.

Marking scheme
  • When the card is parallel to the field lines, so that no lines pass through it.
g.

The light from distant galaxies is redshifted (stretched to redder wavelengths), and the farther the galaxy, the bigger the shift. What does this tell us about the universe?

Answer

The galaxies are moving away from us, the farther ones faster, so the universe is expanding. Run backwards, everything was once packed together, which supports the Big Bang.

Marking scheme
  • The galaxies are moving away, so the universe is expanding (and was once packed together).
h.

The atomic number of element X is 13 and that of element Y is 8. Write the molecular formula of the compound they form.

Answer

X: 2, 8, 3, so its valency is 3. Y: 2, 6, so its valency is 2. Crossing the valencies: X₂Y₃ (this is aluminium oxide, Al₂O₃).

Marking scheme
  • X₂Y₃ (valencies 3 and 2).
i.

In the extraction of aluminium, alumina is melted together with cryolite before electricity is passed. Why?

Answer

Alumina melts only above 2,000 °C. Cryolite lowers its melting point to about 950 °C, which saves a great deal of energy (and the molten mixture also conducts electricity better).

Marking scheme
  • It lowers the melting point (from over 2,000 °C to about 950 °C), saving energy.

Section C

14 × 2 = 28

Write short answers to the following questions.

3.
[2]

Sabina reads that “digital transmission needs a larger bandwidth than analog transmission”. But when the cable company in her town changed from analog to digital, the same cable began to carry five times as many TV channels.

  • i.What is bandwidth?
  • ii.How can digital transmission carry more channels through the same cable?
Answer
  • i.Bandwidth is the range of frequencies that a channel (or a signal) takes up; the wider the bandwidth, the more data it can carry each second.
  • ii.The statement is true only for raw, uncompressed digital sound and video. Before the bits are sent, the encoder compresses the data into as few bits as possible (for example, sending only the parts of a picture that change from one frame to the next). Each compressed channel takes up only a small part of the bandwidth one analog channel needed, so several channels fit into the space of one.
Marking scheme
  • i. The range of frequencies a channel or signal uses (how much data it can carry).
  • ii. The encoder compresses the digital data, so each channel needs much less bandwidth and several fit in the space of one analog channel.
4.
[2]

Write any two characteristics of the animals of class Aves.

Answer

Any two:

  • The body is covered with feathers.
  • The forelimbs are wings; the hind limbs are for walking, perching or swimming.
  • The bones are hollow and filled with air (pneumatic bones).
  • They are homeothermic (warm-blooded), with a four-chambered heart.
  • They breathe with lungs, helped by air sacs.
  • Fertilization is internal, and they lay eggs (oviparous).
Marking scheme
  • One correct characteristic.
  • A second correct characteristic.
5.
[2]

Bees eat about 6–8 kg of honey to make 1 kg of wax. Compare two ways of dividing a comb into cells of the same area, 1 cm² each: square cells, each with sides of 1 cm, and regular hexagonal cells, each with sides of 0.62 cm.

  • i.Find the length of wall around one cell of each shape. About what percentage less wall does a hexagonal cell need?
  • ii.Why does this saving matter to the bees, and why don’t they build round cells, which need even less wall?
Answer
  • i.Square: 4 × 1 cm = 4 cm. Hexagon: 6 × 0.62 cm = 3.72 cm. The hexagon needs 4−3.724×100%=7% \dfrac{4 - 3.72}{4} \times 100\% = 7\% less wall for the same space.
  • ii.Wax is very costly for the bees: each kilogram of it costs them 6–8 kg of honey. Less wall means less wax, so more honey is left as food. Round cells can’t fit together without gaps, which would waste space (and wax around the gaps); of the shapes that fit together with no gaps, the hexagon needs the least wall.
Marking scheme
  • i. 4 cm and 3.72 cm; about 7 % less.
  • ii. Wax costs a lot of honey, so less wax saves food; circles leave gaps (the hexagon uses least wall among shapes with no gaps).
6.
[2]

Write any two differences between a liger and a tigon.

Answer
Liger Tigon
Its father is a lion and its mother a tiger. Its father is a tiger and its mother a lion.
It grows bigger than both its parents (the biggest cats in the world). It is about the size of its parents or a little smaller.
It looks mostly like a lion, with faint stripes. It looks rather like a tiger.
Marking scheme
  • One correct difference (the parents: lion father and tiger mother, or the reverse).
  • A second correct difference (size or looks).
7.
[2]

In pea plants, a green pod (G) is dominant over a yellow pod (g). A pure green-podded plant (GG) is crossed with a yellow-podded plant (gg), and the F₁ plants are self-pollinated.

  • i.Show the F₁ × F₁ cross in a checkerboard.
  • ii.If 1,200 F₂ plants are grown, how many will have yellow pods, and how many will be pure green-podded?
Answer

i. All the F₁ plants are Gg (green). Each makes gametes G and g in equal numbers:

♂ \ ♀ G g
G GG (green) Gg (green)
g Gg (green) gg (yellow)

ii. GG : Gg : gg = 1 : 2 : 1, so green : yellow = 3 : 1. Yellow (gg) = ¼ × 1,200 = 300 plants; pure green (GG) = ¼ × 1,200 = 300 plants (the other 600 are hybrid green, Gg).

Marking scheme
  • i. Checkerboard with gametes G, g from each F₁ parent and offspring GG, Gg, Gg, gg.
  • ii. 300 yellow and 300 pure green.
8.
[2]

When Mendel crossed pure purple-flowered and white-flowered peas and let the F₁ plants self-pollinate, he counted 705 purple-flowered and 224 white-flowered plants in the F₂.

  • i.Work out the ratio of purple to white. What does this ratio tell us about the F₁ plants?
  • ii.The ratio is not exactly 3 : 1. Why not, and why did Mendel count so many plants?
Answer
  • i.705224≈3.15 \dfrac{705}{224} \approx 3.15 , so the ratio is about 3 : 1. That is the ratio from crossing two hybrids, Pp × Pp: so each F₁ plant, though purple, carried a hidden gene for white (p), and made P and p gametes in equal numbers.
  • ii.Which pollen grain fertilizes which egg is a matter of chance, like tossing coins, so the real numbers wander a little from 3 : 1. The more plants are counted, the closer the ratio comes to 3 : 1; with only a few plants, chance could hide the pattern completely.
Marking scheme
  • i. About 3 : 1 (3.15 : 1); the F₁ plants were hybrids (Pp) carrying the gene for white and making P and p gametes equally.
  • ii. Fertilization is by chance, so the numbers vary; a large count brings the ratio close to 3 : 1.
9.
[2]

A bag of rice of mass 3 kg is weighed in Kathmandu on a spring balance, which reads 29.4 N, and on a beam balance, which balances it with 3 kg of standard masses. Both balances and the bag are taken to the Moon, where g = 1.62 m/s².

  • i.What will each balance show on the Moon?
  • ii.Why does one reading change and the other not?
Answer
  • i.Spring balance: W = mg = 3 kg × 1.62 m/s² = 4.86 N. Beam balance: it still balances with 3 kg of standard masses.
  • ii.A spring balance measures weight, the pull of gravity on the bag, which is smaller on the Moon because its g is smaller. A beam balance compares the bag with standard masses; the Moon pulls both sides less by the same factor, so they still balance. It measures mass, which is the same everywhere.
Marking scheme
  • i. 4.86 N on the spring balance; still 3 kg on the beam balance.
  • ii. The spring balance measures weight (depends on g); the beam balance compares masses, and both sides change equally, so mass stays the same.
10.
[2]

Planet P has 4 times the mass of the Earth and 3 times its radius. Rita says, “P is heavier than the Earth, so it must pull things harder.”

  • i.Calculate the acceleration due to gravity on the surface of P. (g on the Earth = 9.8 m/s²)
  • ii.Is Rita right? Explain.
Answer

i. g=GMR2 g = \dfrac{GM}{R^2} . On P the mass is 4M and the radius 3R:
gP=G(4M)(3R)2=49×GMR2=49×9.8≈4.36 m/s2 g_P = \frac{G(4M)}{(3R)^2} = \frac{4}{9} \times \frac{GM}{R^2} = \frac{4}{9} \times 9.8 \approx 4.36\ \text{m/s}^2
ii. No. g depends on the radius as well as the mass, and the radius counts as its square. P’s mass makes g 4 times bigger, but standing 3 times farther from its center makes it 9 times smaller, so P pulls things less than half as hard as the Earth.

Marking scheme
  • i. g_P = (4/9) × 9.8 ≈ 4.36 m/s².
  • ii. No: g ∝ M/R², and the radius squared (9 times) outweighs the mass (4 times).
11.
[2]

Give reasons:

  • i.Steam at 100 °C burns the skin much worse than boiling water at 100 °C.
  • ii.A thick glass tumbler cracks more easily than a thin one when boiling water is poured into it.
Answer
  • i.When steam touches the cooler skin, it condenses into water, and gives out the large extra heat it took in when it boiled (about 2,260 J for every gram) before it even begins to cool. That extra heat goes into the skin, so the burn is deeper.
  • ii.Glass is a poor conductor of heat. The inner surface heats up and expands at once, while the outer surface stays cold and doesn’t expand. In thick glass the difference between the inside and the outside is bigger, so the strain is bigger and the glass cracks.
Marking scheme
  • i. Steam gives out its extra (latent) heat as it condenses on the skin.
  • ii. The inside expands but the outside doesn’t (glass conducts heat poorly); in thick glass the difference is bigger, so it cracks.
12.
[2]

A bulb is placed 40 cm in front of a convex lens of focal length 12 cm. Draw a ray diagram to show where its image forms, and write the nature and position of the image.

Answer

The bulb is beyond 2F₁ (2f = 24 cm). One ray parallel to the axis is bent through F₂; one ray through the optical center O goes straight on. Where they meet is the image:

2F₁F₁F₂2F₂Oprincipal axisobjectreal image
Figure 1 A convex lens with the bulb beyond 2F₁: the image is real, inverted and smaller, between F₂ and 2F₂.

The image is real, inverted and diminished (smaller than the bulb), and it forms on the other side of the lens between F₂ and 2F₂ (in fact about 17 cm from the lens).

Marking scheme
  • A correct ray diagram (two rays from the top of the object meeting beyond F₂).
  • Real, inverted, diminished; between F₂ and 2F₂.
13.
[2]

An empty, clean test tube is dipped at a slant into a beaker of water. Seen from above at a slant, its wall shines like silver. When the test tube is filled with water, the shine disappears.

  • i.Why does the empty test tube shine?
  • ii.Why does the shine disappear when it is filled with water?
Answer
  • i.Light traveling in the water and glass meets the inner wall of the tube, with air behind it, at an angle bigger than the critical angle. It can’t pass into the rarer air, so it is totally internally reflected to our eye, and the wall looks like a mirror.
  • ii.With water inside, there is water on both sides of the thin glass wall and no surface with air behind it. Light goes from water into glass and back into water, a denser medium each time or almost the same, so there is no total internal reflection: the light passes through and the shine is gone.
Marking scheme
  • i. Light meets the glass–air surface at more than the critical angle and is totally internally reflected.
  • ii. With water inside, there is no rarer medium (air) behind the glass, so the light passes through and is not totally reflected.
14.
[2]

The atomic number of iron is 26.

  • i.Write the electronic configuration of iron in subshells.
  • ii.To which block and which period of the modern periodic table does it belong? Give a reason.
Answer

i. Subshells fill in order of energy, and 4s fills before 3d:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
ii. Its last electron enters a d subshell (3d), so it is in the d-block; its outermost shell is the fourth, so it is in period 4.

Marking scheme
  • i. 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶.
  • ii. d-block (last electron in 3d), period 4 (four shells).
15.
[2]

Write the functional group of alcohols and of carboxylic acids, with one example of each.

Answer
  • Alcohols: the hydroxyl group, –OH; for example ethanol, C₂H₅OH.
  • Carboxylic acids: the carboxyl group, –COOH; for example ethanoic acid (acetic acid, in vinegar), CH₃COOH.
Marking scheme
  • Alcohols –OH, with a correct example (methanol, ethanol…).
  • Carboxylic acids –COOH, with a correct example (ethanoic acid…).
16.
[2]

The wastewater from a laundry, full of detergent that contains phosphates, flows into a pond. After some weeks the pond is covered with thick green algae, and dead fish float on it.

  • i.Why did the algae grow so much?
  • ii.Why did the fish die?
Answer
  • i.Phosphates are plant nutrients, like a fertilizer, so the algae in the pond grew and spread very fast.
  • ii.The thick algae die and rot, and the bacteria that decompose them use up the oxygen dissolved in the water (the algae also block the light). Fish need that oxygen to breathe, so they die.
Marking scheme
  • i. Phosphates act as nutrients (fertilizer) for the algae.
  • ii. The algae die and decay, using up the dissolved oxygen the fish need.

Section D

7 × 4 = 28

Write long answers to the following questions.

17.
[4]

Asmita wants to find out how the height from which a steel ball is dropped affects the depth of the dent it makes in sand. She drops the same steel ball from 0.5 m, 1.0 m and 1.5 m onto a tray of damp sand and measures the depth of each dent.

  • i.Name the independent, dependent and any one controlled variable in her experiment. (1)
  • ii.In a second set of trials, she used a bigger steel ball and, as the damp sand had been used up, a tray of dry sand. Why can’t she compare these results with the first set? (1)
  • iii.Her friend writes the speed with which a ball dropped from a height h hits the sand as v=2gh v = \sqrt{\dfrac{2g}{h}} . Asmita writes v=2gh v = \sqrt{2gh} . Check both with units, and say which could be correct. (1)
  • iv.Another student writes v=gh v = \sqrt{gh} . Do its units match? Can a check with units tell her whether this formula is right? (1)
Answer
  • i.Independent variable: the height from which the ball is dropped. Dependent variable: the depth of the dent. Controlled variables (any one): the same ball, the same kind and dampness of sand, the sand smoothed flat each time, the ball let go without pushing.
  • ii.She changed two more things at once (the ball and the sand), as well as the height. If the dents are different, she can’t tell whether the height, the bigger ball or the dry sand caused it, so it isn’t a fair test. Only the independent variable may change.
  • iii.g is in m s⁻² and h in m. For 2g/h \sqrt{2g/h} : m s−2/m=s−2=s−1 \sqrt{\text{m s}^{-2} / \text{m}} = \sqrt{\text{s}^{-2}} = \text{s}^{-1} , which is not a unit of speed, so it is surely wrong. For 2gh \sqrt{2gh} : m s−2×m=m2 s−2=m s−1 \sqrt{\text{m s}^{-2} \times \text{m}} = \sqrt{\text{m}^2\,\text{s}^{-2}} = \text{m s}^{-1} , the unit of speed, so it could be correct (and it is, from v² = u² + 2gh with u = 0).
  • iv.Yes, gh \sqrt{gh} is also in m s⁻¹. But a unit check can’t tell her it is wrong, because numbers have no units: a missing 2 (or ½) slips through. Matching units show only that a formula could be correct; if they don’t match, it is surely wrong.
Marking scheme
  • i. Independent: height; dependent: depth of the dent; one correct controlled variable.
  • ii. She changed the ball and the sand as well as the height, so the effect of height can’t be found (not a fair test).
  • iii. √(2g/h) gives s⁻¹ (wrong); √(2gh) gives m s⁻¹ (could be correct).
  • iv. Its units match, but a unit check can’t catch a missing number like 2, so it can’t prove a formula right.
18.
[4]

Ram Bahadur, 58, gets tired and out of breath when he climbs the stairs. Listening with a stethoscope, his doctor hears a swishing sound (a murmur) along with the normal “lub-dub” of his heart, and tells him that his bicuspid valve doesn’t close properly.

  • i.Where is the bicuspid valve, and what is its job? (1)
  • ii.What makes the “lub” and the “dub” sounds of a heartbeat? (1)
  • iii.When his left ventricle contracts, where does some of the blood go that shouldn’t? (1)
  • iv.Why does this make him tired and breathless? (1)
Answer
  • i.It lies between the left auricle and the left ventricle. It lets oxygenated blood flow from the left auricle into the left ventricle, and stops it from flowing back when the ventricle contracts.
  • ii.They are the sounds of valves shutting: “lub” is the tricuspid and bicuspid valves closing as the ventricles begin to contract; “dub” is the aortic and pulmonary (semilunar) valves closing as the ventricles relax.
  • iii.Because the valve leaks, some blood is pushed back into the left auricle instead of all of it going out through the aorta. (That leaking blood makes the swishing murmur.)
  • iv.Less oxygenated blood goes out through the aorta to his body, so his muscles get less oxygen when they need more, as on the stairs, and he tires quickly. The blood also backs up from the left auricle into the pulmonary veins and the lungs, which makes him breathless.
Marking scheme
  • i. Between the left auricle and left ventricle; lets blood into the ventricle and stops it flowing back.
  • ii. Lub: tricuspid and bicuspid valves closing; dub: aortic and pulmonary valves closing.
  • iii. Back into the left auricle.
  • iv. Less oxygenated blood reaches the body (and blood backs up into the lungs).
19.
[4]

Read the passage and answer the questions.

In 2009, only 121 tigers were counted in Nepal. The country promised to double the number, and protected the tigers’ forests in its national parks and their buffer zones, stopped poaching with army patrols and community guards, and counted the tigers every few years with hundreds of camera traps. The 2026 count found 429 tigers. But the parks are now nearly full, and some tigers come out into nearby villages, where they kill goats and cattle, and sometimes people.

  • i.Is the conservation of tigers in their national parks in-situ or ex-situ conservation? Why? (1)
  • ii.Why does Nepal count its tigers with camera traps every few years? (1)
  • iii.Why are more tigers now coming into the villages? (1)
  • iv.Suggest any two ways to reduce this conflict between tigers and people. (1)
Answer
  • i.In-situ conservation, because the tigers are protected in their own natural habitat (the forests of the national parks), not bred away from it as in a zoo.
  • ii.To know the real state of the species: how many tigers there are, where they live and whether their number is rising or falling, so that conservation can be planned and checked. Camera traps photograph each tiger, and each tiger’s stripes are different, so they can be counted without catching them.
  • iii.The parks are nearly full: there may now be more tigers than the forests can feed, so young tigers looking for their own area, and old or injured ones that can’t hunt wild prey, wander out to where goats and cattle are easy to catch.
  • iv.Any two: pay people quickly and fairly for the animals and lives lost; keep forest corridors so tigers can move between parks instead of through villages; build strong night sheds for livestock; share the parks’ income with the buffer-zone communities (30 to 50 %), so they gain from the tigers; warn people and avoid going alone into the forest at dawn and dusk.
Marking scheme
  • i. In-situ, as they are protected in their natural habitat.
  • ii. To know how many there are and where, and whether conservation is working.
  • iii. The parks are nearly full, so tigers leave them in search of food and space.
  • iv. Any two correct ways (compensation, corridors, livestock sheds, income for the buffer zone, awareness).
20.
[4]

A rectangular wooden block 25 cm long, 8 cm wide and 5 cm high floats in water with its largest face down. 3.5 cm of its height is under the water. (Density of water = 1,000 kg/m³, g = 9.8 m/s²)

  • i.State the law of flotation. (1)
  • ii.Calculate the upthrust on the block. (1)
  • iii.Calculate the density of the wood. (1)
  • iv.The block is put in mustard oil of density 920 kg/m³. How deep will it sink, and will it still float? (1)
Answer
  • i.A floating body displaces liquid whose weight is equal to its own weight.
  • ii.Volume under water = 25 cm × 8 cm × 3.5 cm = 700 cm³ = 0.0007 m³. Upthrust = weight of water displaced = Vρg = 0.0007 × 1,000 × 9.8 = 6.86 N.
  • iii.The block floats, so its weight = upthrust = 6.86 N, and its mass = 6.86 ÷ 9.8 = 0.7 kg. Its whole volume = 25 × 8 × 5 = 1,000 cm³ = 0.001 m³, so its density = 0.7 kg ÷ 0.001 m³ = 700 kg/m³.
  • iv.It must still displace 0.7 kg of liquid: volume of oil = 0.7 ÷ 920 ≈ 0.000761 m³ = 761 cm³. Depth = 761 cm³ ÷ (25 × 8) cm² ≈ 3.8 cm. That is less than its 5 cm height, so it still floats, but sinks a little deeper than in water because the oil is less dense.
Marking scheme
  • i. A floating body displaces liquid equal to its own weight.
  • ii. 6.86 N.
  • iii. 700 kg/m³.
  • iv. About 3.8 cm; still floats, since it is less than 5 cm.
21.
[4]

The graphs show how the current in two wires, X and Y, changes with time.

−4−22400.0250.050current (A)time (s)Wire X−4−22400.0250.050current (A)time (s)Wire Y
Figure 2 Current against time in wire X and in wire Y.
  • i.Which graph shows direct current? Name one source of it. (1)
  • ii.Find the frequency of the current in Y, and how many times a second it changes direction. (1)
  • iii.Starting from zero, how long does the current in Y take to reach its greatest value of 4 A? (1)
  • iv.A magnetic compass is placed just under each wire. How will the needle behave under X and under Y? (1)
Answer
  • i.X: the current stays at 3 A in the same direction all the time. Any one source: a cell, a battery or a solar panel.
  • ii.One cycle of Y takes 0.025 s, so f=1T=10.025 s=40 Hz f = \dfrac{1}{T} = \dfrac{1}{0.025\ \text{s}} = 40\ \text{Hz} . It changes direction twice in each cycle: 80 times a second.
  • iii.It rises from zero to its peak in a quarter of a cycle: 14×0.025 s=0.00625 s \tfrac{1}{4} \times 0.025\ \text{s} = 0.00625\ \text{s} (about 6 ms).
  • iv.Under X the needle turns and stays turned across the wire, because the steady current makes a steady magnetic field. Under Y the field reverses 80 times a second; the needle is too heavy to swing back and forth so fast, and the pushes in the two directions cancel, so it hardly moves from its north–south direction (at most it trembles).
Marking scheme
  • i. X; a correct source (cell, battery, solar panel).
  • ii. 40 Hz; 80 changes of direction a second.
  • iii. 0.00625 s (a quarter of a cycle).
  • iv. X: needle turns and stays deflected; Y: the field reverses too fast, so the needle hardly moves.
22.
[4]

Ammonia for fertilizers is made by the Haber process:
N2(g)+3H2(g)→Fe, high pressure, 450 °C2NH3(g) \text{N}_2(g) + \text{3H}_2(g) \xrightarrow{\text{Fe, high pressure, 450 °C}} \text{2NH}_3(g)

  • i.Which type of chemical reaction is this? Give a reason. (1)
  • ii.What is the role of the iron (Fe)? Why is it written above the arrow and not as a reactant? (1)
  • iii.Why is the reaction carried out at a very high pressure? (1)
  • iv.Why does raising the temperature make the reaction faster? (1)
Answer
  • i.A combination reaction: two substances, nitrogen and hydrogen, combine to form a single new substance, ammonia.
  • ii.Iron is a (positive) catalyst: it speeds up the reaction by giving it a path with a lower energy hill. It is not used up or permanently changed, and comes out at the end as it went in, so it is not a reactant and is written above the arrow.
  • iii.Both reactants are gases. A high pressure squeezes the gas molecules closer together, so they collide more often, and the rate increases.
  • iv.At a higher temperature the molecules move faster, so they collide more often, and, more importantly, a bigger share of the collisions have enough energy (the activation energy) to react.
Marking scheme
  • i. Combination, as two reactants form one product.
  • ii. A catalyst, which speeds the reaction without being used up or changed.
  • iii. Gas molecules are crowded together, so they collide more often.
  • iv. Faster molecules: more collisions, and more of them with enough energy to react.
23.
[4]
  • i.Draw a neat, labeled diagram of a soda-acid fire extinguisher. (2)
  • ii.Write the balanced chemical equation of the reaction inside it. (1)
  • iii.Why should it not be used on an electrical fire or on burning oil? (1)
Answer

i. A strong solution of sodium bicarbonate fills the cylinder; a small glass bottle of concentrated sulphuric acid hangs near the top under a plunger; striking the plunger breaks the bottle, and the carbon dioxide made forces the liquid out through the nozzle.

strike the plungerglass bottle ofconcentratedsulphuric acidsolution of sodiumbicarbonate (NaHCO₃)steel cylindertube from the bottom:the gas pressure abovepushes the liquid outhosenozzlejet of waterand CO₂
Figure 3 A soda-acid fire extinguisher, cut open. Striking the plunger breaks the acid bottle; the carbon dioxide made pushes the liquid out of the nozzle.
  • ii.2NaHCO3+H2SO4→Na2SO4+2H2O+2CO2 2\text{NaHCO}_3 + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O} + 2\text{CO}_2
  • iii.Its jet is mostly water. Water conducts electricity, so on an electrical fire it can give a shock; and oil is lighter than water, so it floats on the water and spreads the fire.
Marking scheme
  • i. Diagram of the cylinder with the nozzle, the plunger and the acid bottle drawn correctly.
  • i. At least three parts labeled (plunger, acid bottle, sodium bicarbonate solution, nozzle).
  • ii. 2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2H₂O + 2CO₂.
  • iii. The jet is mostly water, which conducts electricity and spreads burning oil.

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