Final Exam Model Paper 10

To join them end to end: "Lo " + "Manthang" gives "Lo Manthang".

That ndigits is optional: it may be left out, as in round(7.6). The brackets themselves are never typed.

Short clips are much easier to cut: on the timeline he can choose the best ones, trim each and put them in order, instead of hunting through one long recording for the good moments.

If it goes wrong just after a small part was added, the bug must be in that part, so it is quick to find and fix. With the whole program typed at once, a mistake could be anywhere, and several mistakes get mixed up together.

9,000,000 ÷ 10 = 900,000 bytes, and 900,000 ÷ 1,024 ≈ 879 KB.

Line 4 isn’t part of the decision: it isn’t indented, so it runs every time, whatever the depth. Put else: before it and indent it under the else, so that only one of the two lines is printed:

depth = int(input("Depth of the river in cm: "))if depth < 60:    print("Safe to cross.")else:    print("Too deep: wait.")

Depth of the river in cm: 45Safe to cross.

Hang up and call him back on the number she already has (or ask the family code word) before sending anything. AI can copy a voice from a few seconds of a video, and hurry and secrecy are the signs of a scam.

• i.It prints 14. Line 2 put a copy of morning’s value, 14, into evening. Line 3 changes only morning; evening keeps the 14 it was given.
• ii.It would print 11. Then morning = 11 runs first, so when evening = morning runs, morning already holds 11, and that is the value copied. A variable gets the value the other one has at the moment the line runs.

i. 16 + 18 = 34, and 34 % 24 is the remainder after a whole day of 24 hours, 10:

Arrives at 10 o'clock

ii. A clock starts again at 0 after 24 hours, and % gives what is left over after whole days. For 30 hours, (16 + 30) % 24 is 46 − 24 = 22 o’clock; but it doesn’t tell you which day: that bus would arrive on the day after the next.

i. “Tsarang” is at position 3, so the function returns 3 as soon as it finds it. “Marpha” isn’t in the list, so the loop ends and line 5 returns −1:

3-1

ii. 0 is a real position: the first village, Jomsom. Returning 0 would mean “found at the front”. −1 can never be a position, so it clearly means “not there”.

• i.6,000 ÷ 3 = 2,000 pixels: the banner will be 6,000 × 2,000.
• ii.Yes. The banner has 6,000 pixels across, four times the 1,500 it is shown at, so it is shrunk to fit, never stretched, and keeps its detail.

• i.3: each press of A adds 1 (5 in) and each press of B takes 1 away (2 out), and the display shows the count each time round.
• ii.By polling: the while True: loop goes round again and again, asking about each button every time, many times a second, much faster than anyone can press. was_pressed() gives one True for each press since the last time it asked.

A message about you (what you are looking at, roughly where you are, what is known about you) goes out to many advertisers’ computers; they bid, and the highest bid’s ad appears. It happens again each time an ad appears.
It matters because every company that gets the message receives the data about you, even the ones that lose, and each can add it to what it already knows: one way data brokers build their profiles of people.

Lhamo’s view is the better one. A technology is rarely simply good or bad: it helps some people and costs others, and Lhamo looks at who is helped, who is left out (social) and what it costs (environmental), while Dawa’s claim has no evidence and ignores both. What the community does decides how it turns out: for example, let the school lend devices and run the app on its Wi-Fi so every student can use it, train teachers to use it, and check how much it helps before paying for more.

i.

under_5 = 0middle = 0over_60 = 0age = int(input("Age of the patient (-1 to stop): "))while age != -1:    if age < 5:        under_5 = under_5 + 1    elif age < 60:        middle = middle + 1    else:        over_60 = over_60 + 1    age = int(input("Age of the patient (-1 to stop): "))print("Under 5:", under_5)print("5 to 59:", middle)print("60 and over:", over_60)print("Patients:", under_5 + middle + over_60)

For the ages 3, 34, 67, 45, 80, 1 and 29:

Age of the patient (-1 to stop): 3Age of the patient (-1 to stop): 34Age of the patient (-1 to stop): 67Age of the patient (-1 to stop): 45Age of the patient (-1 to stop): 80Age of the patient (-1 to stop): 1Age of the patient (-1 to stop): 29Age of the patient (-1 to stop): -1Under 5: 25 to 59: 360 and over: 2Patients: 7

ii. With separate ifs, every one is checked, so a child of 3 would pass both age < 5 and age < 60, and be counted twice. With elif, the first true condition wins and the rest are skipped, so each patient is counted once, and elif age < 60 only ever sees ages of 5 and more.

i. For example:

ii. The edge test for the first item, Thorong La. It should be at position 0, but the program prints:

Which pass? Thorong LaThorong La is not in the list.

range(1, len(passes)) starts at 1, so position 0 is never compared: the first pass can never be found. It should be range(len(passes)). The ordinary test, Cho La, and the last item both pass, so only the edge test shows the bug.

• i.It shows the words “The permits you need” as a link; tapping them opens the page permits.html.
• ii.width: 1200px makes every photo 1,200 pixels wide, and border: 3px solid #8b4513 draws a solid line 3 pixels thick round it, in the color #8b4513 (a brown).

iii.

• There are two <h1> headings. A page should have one main heading; “How to get there” is a part of the page, so make it <h2>.
• A fixed width of 1,200 px is far wider than a phone’s screen, so the photo sticks out and the reader must scroll sideways. Use max-width: 100%; instead.

• i.A factory reset, which wipes everything the last owner left on it: their accounts, files and any harmful programs.
• ii.Back it up, sign out of his accounts, then reset it.
• iii.Remove them, or switch them off, and check the permissions of the apps he keeps.
• iv.When the battery is charged, the phone is on Wi-Fi, and he won’t need the phone for about half an hour.

day = 1crossed = Falsewhile day <= 3 and not crossed:    wind = int(input(f"Day {day}: wind on the pass (km/h): "))    if wind < 40:        print("Cross today!")        crossed = True    else:        print("Too windy: wait another day.")        day = day + 1if not crossed:    print("Go back down and try another time.")

Day 1: wind on the pass (km/h): 65Too windy: wait another day.Day 2: wind on the pass (km/h): 50Too windy: wait another day.Day 3: wind on the pass (km/h): 30Cross today!

With 70, 60 and 55:

day = 1crossed = Falsewhile day <= 3 and not crossed:    wind = int(input(f"Day {day}: wind on the pass (km/h): "))    if wind < 40:        print("Cross today!")        crossed = True    else:        print("Too windy: wait another day.")        day = day + 1if not crossed:    print("Go back down and try another time.")

Day 1: wind on the pass (km/h): 70Too windy: wait another day.Day 2: wind on the pass (km/h): 60Too windy: wait another day.Day 3: wind on the pass (km/h): 55Too windy: wait another day.Go back down and try another time.

crossed is a flag: it starts False and becomes True once the group crosses, which ends the loop. Other ways of stopping the loop are fine, and other wordings of the messages.

i. and ii. An IndentationError, on line 3:

  File "main.py", line 3    print("Hire a second herder.")    ^^^^^IndentationError: expected an indented block after 'if' statement on line 2

The lines that belong to an if must be indented under it. Line 3 is not, so Python finds nothing inside the if, and refuses to run any of the program.

iii. Indent line 3 by four spaces. Line 4 stays where it is, so that it runs for every number of yaks:

yaks = int(input("How many yaks? "))if yaks > 10:    print("Hire a second herder.")print("Yaks on the trail:", yaks)

How many yaks? 12Hire a second herder.Yaks on the trail: 12

iv.

One good page (yours will be different):

<!DOCTYPE html><html lang="en">  <head>    <meta charset="utf-8">    <meta name="viewport" content="width=device-width, initial-scale=1">    <title>Visit Upper Mustang</title>    <link rel="stylesheet" href="style.css">  </head>  <body>    <h1>Visit Upper Mustang</h1>    <p>Upper Mustang is a high, dry land north of the Himalaya, once the Kingdom of Lo, with its walled capital, Lo Manthang.</p>    <h2>Things to see</h2>    <ul>      <li>The walled city of Lo Manthang</li>      <li>Old chortens and monasteries painted red and white</li>      <li>Cliffs of red and yellow rock above the Kali Gandaki</li>    </ul>    <img src="mustang.jpg" alt="Old stone chortens with red and white bands on a bare, stony hillside, with gray mountains behind">  </body></html>

body {  font-family: sans-serif;  background-color: #f6efe4;} h1 {  color: #8b2e16;} img {  max-width: 100%;}

The max-width: 100% rule keeps the photo inside a phone’s screen.

• i.It stops when the group has crossed (crossed becomes True) or when day goes past 3. Without day = day + 1, day would stay 1, so on windy mornings day <= 3 would never become False: the program would keep asking, an infinite loop, until a calm morning came.
• ii.The loop can end in two ways: the group crossed, or 3 windy days went by. Only the second should send them down. Without the check, a group that crossed on day 3 (winds 65, 50, 30) would be told “Cross today!” and then “Go back down and try another time.”
• iii.The HTML says what the content is, and the CSS how it looks. With the look in one style sheet, one change there changes every page that uses it, the page stays easy to read and fix, and screen readers and phones still find the headings and lists in the HTML.