← Grade 10 Science

Exam practice

Every question from the end of every unit, with hints and answers to open. After you check an answer, mark how you did, and come back to the ones you didn’t get.

55 questions

Unit 10 · Wave

2. Differentiate between

a.

Reflection of light and total internal reflection of light

Answer
Reflection of light Total internal reflection
Light bounces back from a surface such as a mirror or polished metal. Light inside a denser medium bounces back from its boundary with a rarer medium.
Can happen whichever side the light comes from, at any angle. Happens only from a denser into a rarer medium, at angles greater than the critical angle.
Part of the light is absorbed or passes on, so the reflection is never complete. All the light is reflected; none is lost.
e.g. a plane mirror, a polished steel plate e.g. optical fibers, the sparkle of a diamond
b.

Concave lens and convex lens

Answer
Concave lens Convex lens
Thinner in the middle than at the edges. Thicker in the middle than at the edges.
Diverges (spreads out) light: a diverging lens. Converges (brings together) light: a converging lens.
Its focus is virtual; its focal length and power are negative. Its focus is real; its focal length and power are positive.
Always forms a virtual, erect, diminished image. Forms real or virtual images, depending on where the object is.
Corrects short sight; used in door peepholes. Corrects long sight; used in magnifying glasses, cameras, projectors.
c.

Near point of the eye and far point of the eye

Answer
Near point Far point
The nearest point at which the eye can see clearly. The farthest point at which the eye can see clearly.
About 25 cm for a normal eye. At infinity for a normal eye.
The ciliary muscles are fully contracted; the lens is thickest, with the shortest focal length. The ciliary muscles are relaxed; the lens is thinnest, with the longest focal length.
Moves farther away in long sight and with age. Comes closer in short sight.
d.

Short-sightedness and long-sightedness

Answer
Short-sightedness (myopia) Long-sightedness (hypermetropia)
Near objects are seen clearly; distant objects look blurred. Distant objects are seen clearly; near objects look blurred.
The image of a distant object forms in front of the retina. The image of a near object would form behind the retina.
Caused by a too-long eyeball, or a lens (or cornea) that is too strongly curved. Caused by a too-short eyeball, or a lens that can’t become thick enough.
The far point is closer than infinity. The near point is farther than 25 cm.
Corrected by a concave lens. Corrected by a convex lens.
e.

Color blindness and night blindness

Answer
Color blindness Night blindness
Inability to tell certain colors apart (usually red and green). Inability to see well in dim light or at night.
A defect of the cone cells of the retina. A defect of the rod cells of the retina.
Mainly inherited; it can’t be cured. Mainly caused by a lack of vitamin A, and can usually be prevented or treated with it; sometimes inherited.

3. Give reasons

a.

Between glass and water, glass is considered the denser medium and water the rarer medium.

Answer

Light travels more slowly in glass (2.00 × 10⁸ m/s) than in water (2.25 × 10⁸ m/s); glass has the higher refractive index (1.5 against 1.33). Light going from water into glass bends towards the normal. Of two media, the one in which light is slower is the optically denser one, so glass is denser and water rarer.

b.

A coin placed in a glass of water appears to rise a little.

Answer

Light from the coin passes from water (denser) into air (rarer) and bends away from the normal at the surface. The eye traces the light straight back, so it sees the coin at the point the light seems to come from, which is above the real coin. The apparent depth is less than the real depth (about ¾ of it in water), so the coin seems raised.

c.

Letters on a paper look slightly raised when seen through a glass slab placed on them.

Answer

Light from the letters passes up through the glass and into the air, bending away from the normal as it leaves the glass. Traced back, it seems to come from a point higher than the letters, so they look raised. The apparent depth of the letters is the thickness of the slab divided by the refractive index of glass: through a 3 cm slab, they look only 2 cm deep (3 ÷ 1.5), raised by 1 cm.

d.

Stars twinkle.

Answer

Light from a star passes through many layers of the atmosphere, whose refractive indices are different and keep changing as the air moves. The light is refracted by changing amounts, bent sometimes towards and sometimes away from the normal, so the amount of light reaching the eye and the apparent position of the star keep changing. Because a star is so far away that it is a point of light, this flickering is easy to see: the star twinkles.

e.

The Sun appears on the horizon about two minutes before the actual sunrise.

Answer

Light from the Sun, when it is just below the horizon, enters the atmosphere and passes from rarer into denser layers, bending towards the normal at each. It curves down over the Earth’s surface into the observer’s eye, and seems to come from above the horizon. So the Sun is seen about 2 minutes before it actually rises (and for about 2 minutes after it actually sets).

f.

A diamond shines, but a piece of glass cut to the same shape does not.

Answer

Diamond’s refractive index is high (2.42), so its critical angle is very small (24°). Light entering a well-cut diamond meets its inner faces at more than 24° again and again, is totally internally reflected many times, and comes back out of the top: the diamond sparkles. Glass has a critical angle of 42°, so much of the light meets the back faces at less than that and passes straight out through them instead of being reflected back to the eye.

g.

Sunlight is refracted (and split into colors) when it is passed through a prism.

Answer

Light travels more slowly in glass than in air, so it bends at each face of the prism: it is refracted going in, and again coming out, towards the base. And because the speed of light in glass is different for each color (red fastest, violet slowest), each color bends by a different amount: violet most, red least. So sunlight is not only refracted but dispersed into the seven colors of the spectrum.

h.

A convex lens converges light rays.

Answer

A convex lens is like a stack of prisms with their bases towards the middle of the lens. Each prism bends light towards its base, so all of the lens bends light towards the principal axis. The edges are more steeply tilted than the middle, so they bend light more, and rays parallel to the axis all meet at one point, the principal focus.

i.

A concave lens diverges light rays.

Answer

A concave lens is like a stack of prisms with their bases facing outwards, towards the edges. Each prism bends light towards its base, so every part of the lens bends light away from the principal axis, more near the edges. Parallel rays spread out after the lens as if they came from one point in front of it, the principal focus.

j.

A lack of vitamin A in the body is one of the main causes of night blindness.

Answer

We see in dim light with the rod cells of the retina. They contain a light-sensitive pigment, rhodopsin, made from a protein and vitamin A. Without enough vitamin A, too little rhodopsin is made, the rods can’t respond to dim light, and the person can’t see well at night.

k.

Color blindness occurs when the cone cells of the retina stop functioning.

Answer

Color is detected by three kinds of cone cells, sensitive to red, green and blue light; the brain works out each color by comparing how strongly they respond. If one kind of cone doesn’t work properly (usually the red or green ones), the brain can’t tell apart colors that differ only in that cone’s response, such as red and green. That is color blindness.

4. Answer these questions

a.

What is refraction of light?

Answer

The bending, or change in direction, of light as it passes from one optical medium into another, caused by the change in the speed of light. Light going into a denser medium bends towards the normal; going into a rarer medium, away from it.

b.

Write the laws of refraction of light.

Answer
  1. The incident ray, the normal at the point of incidence, and the refracted ray all lie in the same plane.
  2. For a given pair of media, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant (Snell’s law): sin⁡isin⁡r=μ \dfrac{\sin i}{\sin r} = \mu , the refractive index.
c.

What change is seen in the shape of a pencil that is half dipped in water at a slant? Explain with a ray diagram, and name the process.

Answer

The pencil looks bent (broken) at the water’s surface, and the part under water looks shorter and raised. Light from the part under water passes from water into air and bends away from the normal, so the eye sees each point of it higher than it is (Figure 10.6). The process is the refraction of light.

d.

Light passes from water into air. At the water–air surface, the angle of incidence is 40.5° and the angle of refraction 60°. Draw a ray diagram, and explain why an object outside looks farther away (higher) than it really is to an observer under the water.

Answer
a. Water to airairwaternormal40.5°60°b. Looking up from under waterairwaternormalseems to come from hereeye60°40.5°
Figure 10.46 a. Light from water into air at 40.5°, refracted at 60°, away from the normal. b. The same path the other way: light from an object in the air enters the water at 60° and is refracted at 40.5° towards the normal. The eye under water traces it straight back (dashed), to a point higher than the object.

(Check: sin 60° ÷ sin 40.5° = 0.866 ÷ 0.649 = 1.33, the refractive index of water.) Light from an object above the water bends towards the normal as it enters the water. An observer under the water traces it straight back, along a line steeper than the light’s real path in the air, so the object seems to be higher, farther from the surface, than it really is. To a fish, a fisherman looks taller and farther away.

e.

What is a critical angle?

Answer

The angle of incidence, in the denser medium, for which the angle of refraction in the rarer medium is 90° (the refracted ray just skims along the boundary). It is 42° for glass and 49° for water, against air; sin c = 1/μ.

f.

What is total internal reflection of light?

Answer

When light traveling in a denser medium meets the boundary with a rarer medium at an angle of incidence greater than the critical angle, none of it can get out: all of it is reflected back into the denser medium, obeying the laws of reflection. This is total internal reflection.

g.

Write two conditions necessary for total internal reflection of light.

Answer
  1. The light must be traveling from a denser medium into a rarer medium.
  2. The angle of incidence must be greater than the critical angle for that pair of media.
h.

Data can now be sent very fast through fiber internet. What is the role of total internal reflection in fiber internet?

Answer

Data is turned into flashes of light and sent into the glass core of an optical fiber. The core is surrounded by a cladding of lower refractive index, and the light meets the boundary at more than the critical angle, so it is totally reflected again and again, staying in the core even round bends. Because total internal reflection loses no light, the signal travels tens of kilometers before it needs boosting, carrying huge amounts of data at the speed of light in glass.

i.

In endoscopy, colonoscopy and keyhole surgery, how is total internal reflection used to send light to the internal organs and see them?

Answer

The instruments (endoscope, colonoscope, laparoscope) contain bundles of optical fibers. Light from a lamp is sent along one bundle by total internal reflection, round all the bends of the tube, to light up the organ. Light reflected by the organ travels back along a second bundle, again by total internal reflection, to a camera or eyepiece, so the doctor sees the organ on a screen. So the inside of the body can be seen through the mouth, the rectum or a very small cut, without opening the body.

j.

What is dispersion of light?

Answer

The splitting of white light into its seven colors (violet, indigo, blue, green, yellow, orange and red) when it passes through a prism or a similar transparent object.

k.

Give the reason for the dispersion of light.

Answer

In a medium such as glass, the speed of light depends on its wavelength (its color): red light, with the longest wavelength, travels fastest, and violet, with the shortest, slowest. So the refractive index is different for each color, and each color is bent by a different amount: violet most, red least. The colors separate.

l.

Draw ray diagrams showing:

  • i.refraction of light through a glass slab;
  • ii.dispersion of light through a prism.
Answer
  • i.See Figure 10.2: incident ray AO, refracted ray OB bent towards the normal, emergent ray BC parallel to AO, and the lateral shift CD.
  • ii.See Figure 10.22: white light enters one face, and fans out into the seven colors, red bent least (at the top) and violet most (at the bottom).
m.

A person wonders why a rainbow always looks like a semicircle and is always the same size. Explain, including where the Sun is, where the water drops are, and the dispersion of light.

Answer

A rainbow is seen when the Sun is behind the observer and there are water drops in the air in front (after rain). Sunlight entering each drop is refracted and dispersed, reflected from the back of the drop, and refracted again as it comes out. Each color leaves at its own angle: red at about 42° and violet at about 40° to the direction of the sunlight (Figure 10.24).
So the observer receives red light only from drops lying at 42° from the line joining the Sun, the observer’s head and the point directly opposite the Sun (the antisolar point). All such drops lie on a circle around that line, so the rainbow is always a circle of the same angular size, 42° in radius (Figure 10.25). The antisolar point is below the horizon, so the ground hides the lower part of the circle and we see an arc; when the Sun is on the horizon, exactly a semicircle. From an airplane, a full circle can be seen.

n.

Define these terms related to lenses:

  • i.center of curvature
  • ii.optical center
  • iii.principal axis
  • iv.focus
Answer
  • i.Center of curvature: the center of the sphere of which a curved surface of the lens is a part.
  • ii.Optical center: the point at the center of the lens, on the principal axis, through which light passes without bending.
  • iii.Principal axis: the straight line passing through the optical center and the centers of curvature of the lens.
  • iv.Principal focus: the point on the principal axis where rays parallel to the principal axis meet (convex lens), or seem to come from (concave lens), after passing through the lens.
o.

What is meant by the power of a lens?

Answer

The power of a lens is its ability to converge or diverge light rays. It is the reciprocal of its focal length in meters, P=1f P = \dfrac{1}{f} , and is measured in diopters (D). Convex lenses have positive power, concave lenses negative.

p.

The powers of two convex lenses are +2 D and +4 D.

  • i.Which is thicker? Give a reason.
  • ii.Calculate the focal length of each lens.
Answer
  • i.The +4 D lens is thicker. A greater power means a shorter focal length, which needs more strongly curved surfaces, so (for the same glass) a thicker lens.
  • ii.f=1P f = \dfrac{1}{P} : for +2 D, f=12=0.5 m=50 cm f = \dfrac{1}{2} = 0.5\ \text{m} = 50\ \text{cm} ; for +4 D, f=14=0.25 m=25 cm f = \dfrac{1}{4} = 0.25\ \text{m} = 25\ \text{cm} .
q.

When is the image formed by a convex lens real and the same size as the object? Show the ray diagram.

Answer

When the object is at 2F₁, twice the focal length from the lens. The image is formed at 2F₂ on the other side: real, inverted and the same size.

2F₁F₁F₂2F₂Oprincipal axisobjectreal image
Figure 10.47 An object at 2F₁ of a convex lens: a real, inverted image of the same size at 2F₂.
r.

A man on the bank throws a spear at a fish he sees in the water. Will it hit the fish? Explain using the real depth of the fish.

Answer

No: the spear will pass above the fish. Light from the fish bends away from the normal as it leaves the water, so the man sees the fish higher up than it really is (the apparent depth is less than the real depth). He aims at the image, and the spear, which travels straight and doesn’t bend, goes above the real fish. He should aim below where the fish seems to be. (People who fish with spears learn this by experience.)

airwaterthe real fishwhere it seems to bethe spear passes above the fish
Figure 10.48 The man sees the fish where the light seems to come from, higher than it really is. A spear thrown at that point passes above the fish.
s.

Light can be made to zigzag along inside a curved glass tube, following its bends. What process is this? Name two devices that work on it.

Answer

Total internal reflection of light: the light meets the walls at more than the critical angle and is totally reflected each time, so it follows the curved tube. Devices: optical fiber cables (for internet and telephone) and the endoscope (also the colonoscope and laparoscope; periscopes and binoculars use it in prisms).

t.

Complete these ray diagrams:

  • i.light from air at A meeting water at O;
  • ii.light in water meeting the surface at 48.8°;
  • iii.light falling square on to the short face of a 30°–60°–90° glass prism;
  • iv.light P falling square on to the long face (at Q) of a right-angled isosceles prism ABC;
  • v.red light falling on an equilateral prism;
  • vi.an object beyond 2F in front of a convex lens.
Answer
(i) From air into waterairwaternormalirbends towards the normal(ii) At 48.8° in waterairwaternormal48.8°90°the critical angle: it grazes the surface
Figure 10.49
  • i.From air into water, the light bends towards the normal.
  • ii.48.8° is water’s critical angle (sin c = 1/1.33 gives 48.75°), so the refracted ray grazes along the surface, at 90° to the normal; a little more and it would be totally reflected.
60°30°(iii) 30°–60°–90° prismone total internal reflection (○)ABCPQ(iv) Isosceles, right-angledtwo total internal reflections (○)(v) Red light, equilateral prismbends towards the base, no splitting
Figure 10.50 (iii) The light goes straight in and meets the long face at 60°, more than 42°: it is totally reflected, then meets the bottom face at 30° and is refracted out (at 49°). (iv) In at Q without bending, totally reflected at AB and again at BC (both at 45°), and out through AC without bending, going back the way it came. (v) Red light is one color, so it is refracted towards the base at each face but not split.
2F₁F₁F₂2F₂Oprincipal axisobjectreal image
Figure 10.51 (vi) An object beyond 2F₁: a real, inverted, diminished image between F₂ and 2F₂.
u.

Here are three uses of lenses: a hand lens burning paper in sunlight, a magnifying glass, and a door peephole. Write the facts about each, with ray diagrams.

Answer

Burning paper: a convex lens; the Sun is at infinity, so its parallel rays are brought together at the focus F, forming a real, tiny, very bright and hot image of the Sun that can set paper alight. (The case “at infinity” in the ConvexLensCases widget.)

Magnifying glass: a convex lens with the object placed between F and the lens; it forms a virtual, erect, magnified image on the same side as the object, seen by looking through the lens.

2F₁F₁F₂2F₂Oprincipal axisobjectvirtual imageeye
Figure 10.52 A magnifying glass: an object between F₁ and O gives a virtual, upright, magnified image.

Door peephole: a concave lens (in a real peephole, a combination of lenses that acts like one); whatever is outside the door, it forms a virtual, erect, diminished image (Figure 10.31), so a wide view of the doorstep fits in the small lens.

v.

White light is dispersed by a triangular prism onto a screen, with the color X lowest and Y highest.

  • a.Which colors are X and Y?
  • b.Why is Y bent less than X as the light comes out of the prism?
Answer
  • a.X is violet (bent most, lowest) and Y is red (bent least, highest).
  • b.Red light has a longer wavelength and travels faster in glass than violet, so the refractive index of glass is smaller for red. Red is bent less at each face of the prism, so Y is deviated less than X.
w.

How can light dispersed by a prism be turned back into white light?

Answer

Place a second, identical prism upside down next to the first (Figure 10.23). It bends each color back by the same amount the first bent it, so the colors recombine and come out as white light, parallel to the light that entered. (A spinning Newton’s disc shows the same idea: the seven colors together look white.)

x.

Two lenses have focal lengths of 20 cm and −20 cm. What kind of lens is each? Which forms a virtual, magnified image of an object placed 16 cm away? Explain with a scale ray diagram.

Answer

The lens of focal length +20 cm is convex; the lens of −20 cm is concave.
The convex lens forms a virtual, magnified image, because the object (16 cm) is closer than its focus (20 cm): it acts as a magnifying glass. (A concave lens always gives a diminished image.)

2F₁F₁F₂2F₂Oprincipal axisobjectvirtual imageeye
Figure 10.53 To scale: a convex lens of focal length 20 cm, object 16 cm away. The rays spread out after the lens; traced back, they meet 80 cm in front of the lens, giving a virtual, upright image 5 times as tall as the object.

Measured from the scale drawing (or found with the lens formula: 1v=120−116=−180 \tfrac{1}{v} = \tfrac{1}{20} - \tfrac{1}{16} = -\tfrac{1}{80} ), the image is 80 cm from the lens on the same side as the object, and 80 ÷ 16 = 5 times as tall. (The concave lens would give a virtual, upright image 8.9 cm from the lens, about half the size.)

y.

Write the functions of these parts of the eye:

  • i.ciliary muscle
  • ii.cornea
  • iii.lens
  • iv.iris
  • v.pupil
  • vi.retina
Answer
  • i.Ciliary muscle: changes the thickness, and so the focal length, of the eye lens, to focus near and distant objects on the retina (accommodation).
  • ii.Cornea: the clear front window of the eye; it lets light in and does most of the bending of light (about two-thirds of the eye’s focusing).
  • iii.Lens: fine-tunes the focus, bringing the light to a sharp image on the retina.
  • iv.Iris: the colored ring of muscle that controls the size of the pupil, and so how much light enters.
  • v.Pupil: the hole in the iris through which light enters the eye.
  • vi.Retina: the light-sensitive layer where the image forms; its rods (dim light) and cones (color) turn light into electrical signals sent to the brain by the optic nerve.
z.

Write two problems that may be caused by an injury to the cornea.

Answer

Any two: a corneal ulcer (keratitis), an infected sore that can lead to blindness if not treated quickly; corneal edema, fluid between the layers making the cornea cloudy and vision blurred; scarring that leaves the cornea cloudy; a change in its shape (as in keratoconus) causing defects of vision.

27.

A student sitting in a classroom shifts his eyes from the letters on the whiteboard to a distant object seen out of the window. Explain the role of the ciliary muscles in the change of thickness of the eye lens.

Answer

Looking at the whiteboard, which is fairly near, the ciliary muscles are partly contracted, so the lens is fairly thick, with a shorter focal length, to focus the spreading light from the board on the retina. When he looks at the distant object, the ciliary muscles relax; the suspensory ligaments pull the lens thinner, its curvature decreases and its focal length increases, so the nearly parallel light from far away is focused on the retina. This automatic adjustment is accommodation.

28.

In a person’s eye, light from a nearby object (at the normal near point, 25 cm) forms an image behind the retina. Name the defect of vision, give two causes, and explain its correction.

Answer

The defect is long-sightedness (hypermetropia).
Causes:

  1. the eyeball is too short, so the retina is too close to the lens;
  2. the lens can’t become thick enough (its focal length stays too long), because the ciliary muscles are weak or the lens has stiffened, as in old age.

Correction: a convex lens of suitable power is worn in front of the eye. It converges the light from a near object a little before it enters the eye, so that the light seems to come from the eye’s own (farther) near point, and the eye can focus it on the retina (Figure 10.35).

29.

A student can’t read the letters on the whiteboard from the last bench, but reads them clearly from the first bench.

  • i.What defect of vision does he have?
  • ii.Draw a ray diagram of it.
  • iii.Write two reasons for it.
  • iv.Explain, with a ray diagram, the role of the lens that corrects it.
Answer
  • i.Short-sightedness (myopia).
  • ii.See Figure 10.34a: parallel light from the distant board is focused in front of the retina.
  • iii.Two reasons:
  1. the eyeball is too long, so the retina is too far from the lens;
  2. the eye lens (or the cornea) is too strongly curved, so its focal length is too short even when the ciliary muscles are relaxed.

(iv) A concave lens spreads the parallel rays from the board a little before they enter the eye, so they seem to come from the eye’s far point, and are focused on the retina (Figure 10.34c).

30.

Explain, with a ray diagram, the role of the lens used to correct long-sightedness.

Answer

A long-sighted eye can’t focus light from a near object at 25 cm: it would be focused behind the retina. A convex lens placed in front of the eye converges the light a little before it enters, so that it seems to come from the eye’s own near point, farther away, which the eye can focus on the retina (Figure 10.35c). Its power is chosen to match: for a near point of 1 m, +3 D.

31.

A student concludes that “the defect of vision is greater for a person wearing spectacles with thick lenses than for one wearing thin lenses.” Is this correct? Give reasons.

Answer

Generally yes. A thicker lens is more strongly curved, so it has a shorter focal length and a greater power. A more serious defect needs a more powerful lens to correct it: a very short-sighted eye needs a strong concave lens (thick at the edges), a very long-sighted eye a strong convex lens (thick in the middle). So thick lenses usually mean a large defect. (One caution: lenses made of high-index glass or plastic bend light more, so they can correct the same defect with a thinner lens. It is the power, in diopters, that really measures the defect, not the thickness.)

32.

Compare the use of spectacles and contact lenses to correct defects of vision.

Answer
Spectacles Contact lenses
Easy to put on and take off; need little care. Need careful cleaning, disinfecting and storing; hands must be washed.
High-power lenses are thick and heavy. Thin and light, even for high powers.
Vision through the edges is distorted when looking sideways; the frame limits the view. Move with the eye, so the view is clear in every direction.
No risk to the eye. Careless use (dirty lenses, sleeping in them) can infect or damage the cornea.
Can get wet or fog up; awkward in sports. Convenient in sports and in the rain.
33.

Explain the laser surgery method used to solve eyesight problems.

Answer

Laser eye surgery corrects defects of vision by reshaping the cornea, which does most of the eye’s focusing, with an ultraviolet excimer laser. For short sight, the laser removes a very thin layer from the middle of the cornea, making it flatter: it bends light less, and the image moves back onto the retina. For long sight, the laser works on the edges, so the middle bulges a little more and bends light more. In the most common method, LASIK, a thin flap is cut in the front of the cornea and folded back, the laser reshapes the cornea beneath, and the flap is laid back in place to heal (Figure 10.37).

34.

What is a cataract? What is the role of the intraocular lens developed by Nepal’s eye surgeon Dr Sanduk Ruit in the treatment of cataracts?

Answer

A cataract is a cloudiness of the eye lens, usually in old age, when its proteins clump together. Light can’t pass cleanly to the retina, vision becomes blurred, and in the end the person goes blind; a gray or milky patch is seen in the pupil.
It is treated by surgery: the cloudy lens is removed and replaced by a small artificial intraocular lens (IOL) of acrylic or silicone, which focuses light on the retina again. Imported IOLs used to cost about 100 US dollars, too much for most patients in Nepal. In 1995, Dr Sanduk Ruit’s Tilganga Eye Centre in Kathmandu began making good-quality IOLs for about 4 dollars, and he developed a quick, stitch-free way of operating. This made cataract surgery cheap enough for poor and remote patients, and has given sight back to hundreds of thousands of people in Nepal and other countries.

5. Solve these problems

a.

The speeds of light in air and glass are 3 × 10⁸ m/s and 2 × 10⁸ m/s. Calculate the refractive index of glass with respect to air.

Answer

μ=cv=3×108 m/s2×108 m/s=1.5 \mu = \frac{c}{v} = \frac{3 \times 10^8\ \text{m/s}}{2 \times 10^8\ \text{m/s}} = 1.5
The refractive index of glass is 1.5.

b.

The refractive index of diamond is 2.42. If the speed of light in air is 3 × 10⁸ m/s, calculate the speed of light in diamond.

Answer

v=cμ=3×108 m/s2.42=1.24×108 m/s v = \frac{c}{\mu} = \frac{3 \times 10^8\ \text{m/s}}{2.42} = 1.24 \times 10^8\ \text{m/s}

c.

A ray of light falls on a plastic block at 45° to the normal, and the angle of refraction is 33°. Calculate the refractive index of the plastic.

Answer

μ=sin⁡isin⁡r=sin⁡45∘sin⁡33∘=0.70710.5446=1.30 \mu = \frac{\sin i}{\sin r} = \frac{\sin 45^\circ}{\sin 33^\circ} = \frac{0.7071}{0.5446} = 1.30

d.

Calculate the power of a lens of focal length 25 cm.

Answer

f=25 cm=0.25 m f = 25\ \text{cm} = 0.25\ \text{m}
P=1f=10.25 m=+4 D P = \frac{1}{f} = \frac{1}{0.25\ \text{m}} = +4\ \text{D}
(Taking the lens as convex, the usual meaning when no sign is given.)

e.

The lenses of a student’s spectacles have a power of −6 D. Calculate their focal length, and say what kind of lens they are.

Answer

f=1P=1−6 D=−0.1667 m=−16.67 cm f = \frac{1}{P} = \frac{1}{-6\ \text{D}} = -0.1667\ \text{m} = -16.67\ \text{cm}
The focal length is −16.67 cm: a concave lens, so the student is short-sighted. The minus sign is what tells you the lens is concave.